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Ber [7]
3 years ago
12

.) List the molecules of elements in the sample of air. Give the

Physics
1 answer:
Ksivusya [100]3 years ago
8 0

Answer:

Explanation: N2 Nitrogen, O2 Oxygen, Ar does not form molecules

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One method of determining the location of the center of gravity of a person is to weigh the person as he/she lies on a board of
andrey2020 [161]

Answer:

x = 1.018 m

Explanation:

given,

height of man = 190 cm

                       = 1.9 m

scale reading on left = 450 N

scale reading on the right = 390 N

Let center of gravity of man be x distance from feet, feet is on right side.

For system to be in equilibrium moment about center should be equal to zero.

∑M = 0

now,

450(1.9 - x ) - 390 × x = 0

450(1.9 - x ) = 390 × x

855 - 450 x = 390 x

840 x = 855

 x = \dfrac{855}{840}

 x = 1.018 m

hence, point of center of gravity from feet is equal to x = 1.018 m

7 0
4 years ago
A falling stone is at a certain instant 90 feet above the ground. two seconds later it is only 10 feet above the ground. if it w
choli [55]

The equation relevant to this is:

S(t) = So + Vot - At²/2 <span>

</span>

<span>Therefore we can create two equations:
<span>S(t) = 90 = So - 4t - 16.1t²                                      --> eqtn  1</span>
<span>S(t+2) = 10 = So - 4(t+2) - 16.1(t+2)²                     --> eqtn 2</span>

</span>

<span>Expanding eqtn 2:
10 = So - 4t - 8 - 16.1(t² + 4t + 4) 
10 = So - 4t - 8 - 16.1t² - 64.4t - 64.4 
10 + 8 + 64.4 = So - 68.4t - 16.1t² 
<span>82.4 = So - 68.4t - 16.1t²                                        --> eqtn 3</span></span>

 <span>
Subtracting eqtn 1 by eqtn 3:</span>

 90 = So - 4t - 16.1t² 

82.4 = So - 68.4t - 16.1t²

 

=> 7.6 = 64.4t

t = 0.118 s

 

Therefore calculating for initial height So:<span>

<span>82.4 = So - 68.4(0.118) - 16.1(0.118)²

<span>So = 90.7 ft</span></span></span>

7 0
3 years ago
describe how you would connect a voltmeter to measure the potential difference across a resistor and an ammeter to measure the c
Vesna [10]

A voltmeter needs to be connected in parallel to the two sites in order to measure the potential difference between them.

<h3>What is a voltmeter?</h3>
  • The electrical potential difference between two locations in an electric circuit is measured using a voltmeter.
  • The potential difference between two ends of a current-carrying conductor is measured using a voltmeter.
  • On a scale that is typically measured in volts, millivolts (0.001 volts), or kilovolts, a voltmeter primarily monitors the voltage of direct or alternating electric current (1,000 volts).
  • Numerous voltmeters are digital and display readings as numbers.
<h3>How is a voltmeter connected?</h3>
  • A galvanometer with high resistance is a voltmeter.
  • Any portion of an electrical circuit can be measured.
  • Due to its high resistance, it is linked in parallel so that it does not impact the circuit's overall net resistance and does not draw any current by itself.
  • A device's voltage is measured by a voltmeter connected in parallel, and its current is measured by an ammeter connected in series.

Learn more about voltmeters here

brainly.com/question/83321

#SPJ4

3 0
2 years ago
In dim light
faltersainse [42]

The Answer is A, the iris dilates the pupil.

4 0
3 years ago
Read 2 more answers
At time t=0 a positively charged particle of mass m=3.57 g and charge q=9.12 µC is injected into the region of the uniform magne
larisa [96]

Answer:

10.78 s

Explanation:

The force on the charge is computed by using the equation:

F^{\to}= qE^{\to} +q (v^{\to} + B^{\to}) \\ \\  F^{\to} = (9.12 \times 10^{-6}) *278 (-\hat k) +9.12 *10^{-6} *2.1 *0.18 (\hat i * \hat k) \\ \\  F^{\to} = -2.535 *10^{-3} \hat k -3.447*10^{-6} \hat j

F = ma

∴

a ^{\to}= \dfrac{F^{\to}}{m}

a ^{\to}= \dfrac{-1}{3.57\times 10^{-3}}(2.535*10^{-3}\hat k + 3.447*10^{-6} \hat j)

a ^{\to}=-0.710 \hat k -9.656*10^{-4} \hat j

At time t(sec; the partiCle velocity becomes v(t) = 3.78 v_o

The velocity of the charge after the time t(sec) is expressed by using the formula:

v^{\to}= v_{o \ \hat i} + a^{\to }t \\ \\  \implies (2.1)\hat i -0.710 t \hat k -9.656 \times 10^{-4} t \hat j = 3.78 v_o \\ \\ \implies (2.1)^2 +(0.710\ t)^2+ (9.656 *10^{-4}t )^2 = (3.78 *2.1^2 \\ \\ \implies 4.41 +0.5041 t^2 +9.324*10^{-7} t^2 = 63.012 \\ \\ \implies 4.41 +0.5041 t^2 = 63.012\\  \\  0.5041t^2 = 63.012-4.41 \\ \\ t^2 = \dfrac{58.602}{0.5041} \\ \\ t^2 = 116.25 \\ \\ t = \sqrt{116.25} \\ \\  \mathbf{t = 10.78 \ s}

8 0
3 years ago
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