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2 years ago

14

Let the period of evolution of a planet at a distance R from a star be T. Prove that if it was at a distance of 2R from the star

, its period of revolution will be √8 T.

1 answer:

CaHeK987 [17]2 years ago

7 0

Explanation:

8T BR 45 Yeuslilshshbe

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If you apply an equal force to a larger mass, it will take longer to accelerate. <br> Tru or false

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Answer:

true

Explication:

The acceleration of an object depends on the mass of the object, and the amount of force applied

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2 years ago

A baseball with a mass of 0.3kg is thrown into the air with a speed of 50 m/s and is at a height of 10m above. What is the speed

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3 years ago

A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V. What are (a) the total energy stored i

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Answer:

(A) Total energy will be equal to $0.044\times 10^{-5}J$

(b) Energy density will be equal to $0.0175J/m^3$

Explanation:

We have given diameter of the plate d = 2 cm = 0.02 m

So area of the plate $A=\pi r^2=3.14\times 0.02^2=0.001256m^2$

Distance between the plates d = 0.50 mm = $0.50\times 10^{-3}m$

Permitivity of free space $\epsilon _0=8.85\times 10^{-12}F/m$

Potential difference V =200 volt

Capacitance between the plate is equal to $C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 0.001256}{0.50\times 10^{-3}}=0.022\times 10^{-9}F$

(a) Total energy stored in the capacitor is equal to

$E=\frac{1}{2}CV^2$

$E=\frac{1}{2}\times 0.022\times 10^{-9}\times 200^2=0.044\times 10^{-5}J$

(b) Volume will be equal to $V=Ad$ , here A is area and d is distance between plates

$V=0.001256\times 0.02=2.512\times 10^{-5}m^3$

So energy density $=\frac{Energy}{volume}=\frac{0.044\times 10^{-5}}{2.512\times 10^{-5}}=0.0175J/m^3$

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3 years ago

A student puts a beaker of boiling water where it touches a block of ice. Which two statements are true? A. Thermal energy will

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Answer: C and D

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3 years ago

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1 year ago