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sesenic [268]
2 years ago
14

Let the period of evolution of a planet at a distance R from a star be T. Prove that if it was at a distance of 2R from the star

, its period of revolution will be √8 T.
Physics
1 answer:
CaHeK987 [17]2 years ago
7 0

Explanation:

8T BR 45 Yeuslilshshbe

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Unpolarized light passes through two Polaroid sheets. The transmission axis of the second polarizing filter makes an angle of 34
IceJOKER [234]

This question is incomplete, the complete question is;

Unpolarized light passes through two Polaroid sheets. The transmission axis of the second polarizing filter makes an angle of 34° with the axis of the first polarizer. What fraction of the original unpolarized light is transmitted through the second polarizing filter?

Answer: the fraction of the original unpolarized light transmitted through the second polarizing filter is 0.343

Explanation:

We know that when Unpolarized light passes through first polarizer, it's intensity will be reduced to half  i.e

I1 = I0/2

Now after that when light passes through 2nd polarizer, Intensity will be;

I2 = I1 × (cos A1)²  

but  I1 = I0/2

so

I2 = (I0/2) × (cos A1)²

I2/I0 = 0.5 × (cos A1)²

In the question we were given that; The transmission axis of the second polarizing filter makes an angle of 34° with the axis of the first polarizer

so A = 34°

so we substitute

I2/I0 = 0.5 × (cos 34)²

I2/I0 = 0.343

Therefore the fraction of the original unpolarized light transmitted through the second polarizing filter is 0.343

3 0
2 years ago
The escape velocity of a bullet from the surface of planet Y is 1695.0 m/s. Calculate the escape velocity from the surface of th
serg [7]

The escape velocity from the surface of the planet X is 2,249.2 m/s.

<h3>Escape velocity of planet X</h3>

v = \sqrt{\frac{2GM}{r} } \\\\v^2 = \frac{2GM}{r}\\\\v^2r = 2GM\\\\G = \frac{v^2r}{2M}

where;

  • M is mass of the planet
  • r is radius of the planet
  • G is universal gravitation constant

\frac{v_x^2 \ r_x}{2M_x} = \frac{v_y^2 \ r_y}{2M_y} \\\\\frac{v_x^2 \ r_x}{M_x} = \frac{v_y^2 \ r_y}{M_y} \\\\v_x^2 =  \frac{v_y^2 \ r_yM_x}{M_yr_x}\\\\v_x^2 = \frac{(1695)^2 (r_y)(1.59M_y)}{M_y(0.903r_y)} \\\\v_x^2 = 5,058,814.78\\\\v_x = \sqrt{5,058,814.78} \ \ = 2,249.2 \ m/s

Thus, the escape velocity from the surface of the planet X is 2,249.2 m/s.

Learn more about escape velocity here: brainly.com/question/13726115

#SPJ1

6 0
1 year ago
In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the sys
son4ous [18]

Answer:

2500 J

Explanation:

We can solve the problem by using the first law of thermodynamics:

\Delta U =U_f - U_i =Q-W

where

Uf is the final internal energy of the system

Ui is the initial internal energy

Q is the heat added to the system

W is the work done by the system

In this problem, we have:

Q = +1000 J (heat that enters the system)

W = +500 J (work done by the system)

Ui = 2000 J (initial internal energy)

Using these numbers, we can re-arrange the equation to calculate the final internal energy:

U_f = U_i + Q-W=2000 J+1000 J-500 J=2500 J

3 0
3 years ago
Please write something<br><br> What to do in case of a fire.<br> ~write a few sentences~
Zarrin [17]
Follow stop drop and roll if the fire is in the room
Other wise exit immediately and find the nearest fire point. Then when you are out phone the fire services.
I hope this helps :)
5 0
2 years ago
Read 2 more answers
True or False
Ann [662]
The is true because I said so
7 0
2 years ago
Read 2 more answers
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