<span>x=<span><span>3<span> or </span></span>x</span></span>=<span><span>−1/</span><span>2 let me know if it was wrong </span></span>
Answer:
.46 moles
Explanation:
PV = n RT make sure you use the correct R = 8.31446 L-kPa/(K-mol)
36 * 38 = n * 8.31446 * (273.15 + 82)
n = .463 moles
Answer: formic acid
Explanation:
HCOOH is the structural formula for the compound commonly known as formic acid.
According to the international union of pure applied chemist (IUPAC), it is named methanoic acid, and represent the first member of the alkanoic acids.
Thus, examples of alkanoic acids are
- formic acid (HCOOH)
- Acetic acid (CH3COOH)
- Propanoic acid (CH3CH2COOH) etc
<u>Answer:</u> The empirical formula for the given compound is
<u>Explanation:</u>
We are given:
Mass of beaker, = 204.35 g
Mass of beaker and lead before the reaction, = 214.71 g
Mass of beaker and lead chloride after the reaction, = 218.26 g
Mass of lead = = [214.71 - 204.35] = 10.36 g
Mass of chlorine = = [218.26 - 214.71] = 3.55 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Lead =
Moles of Chlorine =
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.05 moles.
For Lead =
For Chlorine =
- <u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of Pb : Cl = 1 : 2
Hence, the empirical formula for the given compound is
Answer:
a.
Explanation:
because
beds Go to <URL> to see if the