2 years ago

PLEASE ANSWER!! DUE IN A FEW MINUTES!! DON'T FORGET TO SHOW YOUR WORK AS WELL!!!!!!!!

Mathematics

1 answer:

IrinaK [193]2 years ago

5 0

I’ve attached my work
Hope it helps!

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In january of one winter, 3/10 of a wood pile was used in a wood stove. In February, 2/5 of the wood pile was used. What part of

arsen [322]

2/5 is equivalent to 4/10 so at the end of February 4/10 was used up
And at the end of January, 3/10 was used
so 4/10 + 3/10 = 7/10

At the end of February, 7/10 of the wood was used

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2 years ago

Simplify the sum.<br> (4u3 + 4u2 + 2) + (6u3 – 2u + 8)

Elan Coil [88]

Answer:

$10u^{3}+4u^{2}-2u+10$ or $2(5u^{3}+2u^{2}-u+5)$

Step-by-step explanation:

we have

$(4u^{3}+4u^{2} +2)+(6u^{3}-2u+8)$

step 1

Group terms that contain the same variable

$(4u^{3}+6u^{3})+(4u^{2})+(-2u)+(2+8)$

step 2

Combine like terms

$(10u^{3})+(4u^{2})+(-2u)+(10)$

step 3

Eliminate parenthesis

$10u^{3}+4u^{2}-2u+10$

step 4

Factor the number $2$

$2(5u^{3}+2u^{2}-u+5)$

8 0

2 years ago

Read 2 more answers

This is hard and I need help

AleksAgata [21]

I think it is 40x16=640

Answer = 64:0

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2 years ago

WILL MARK YOU BRAINLIEST!!!!

Ad libitum [116K]

Answer:

the slope would be 0

Step-by-step explanation:

3 0

3 years ago

There is 20 houses on Essex Street. Every third house has a streetlight in front of it. How many houses do not have a streetligh

Mrrafil [7]

14 houses does not have street light
20/3~6
20-6=14

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2 years ago