Answer:
65.625 m/s
Explanation:
c = Speed of light = 3×10⁸ m/s
Relative speed
Relative speed = 35.625 m/s
Velocity of speeder = Velocity of police car + Relative speed
⇒Velocity of speeder = 30 + 35.625 = 65.625 m/s
∴ Velocity of speeder is 65.625 m/s
Momentum = mass x velocity
Before collision
Momentum 1 = 2 kg x 20 m /s = 40 kg x m/s
Momentum 2 = 3 kg x -10m/s = -30 kg x m/s
After collision
Momentum 1 = 2 kg x -5 m/s = -10 m/s
Momentum 2 = 3 kg x V2 = 3V2
Total momentum before = total momentum after
40 + -30 = -10 + 3V2
V2 = <span>6.67 m/s
Total kinetic energy before
</span><span>= (1/2) [ 2 kg * 20 m/s * 2 + 3 kg * ( -10 m/s) *2 ]
= 550 J
</span>
<span>Total kinetic energy after
</span>= (1/2) [ 2 kg * ( - 5 m/s) * 2 + 3 kg * 6.67 m/s *2 ]
= 91.73 J
Total kinetic energy lost during collision
=<span>550 J - 91.73 J
= 458.27 J</span>
The type of conversion that is taking place when natural gas is
burned to heat water is referred to as chemical conversion. In this
conversion thermal energy is produced.
The potential energy would be zero. Only kinetic energy is present in this case. To find out what the answer is we do the equation: mv^2/2 soo...
KE =mv^2/2
KE= 1(2^2)/2 which the answer will come up by 2 Joules.
5 is 4) shallow water, 6 is 2)sedimentary i think but I'm not 100% sure and 7 is 21%
