Can anyone help with this physics question?
1 answer:
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Answer:
The distance between the lighthouse and the ship
from the start position A = 5.08 miles
from the Final point B = 7.23 miles
Explanation:
Note: Refer the figure
Let the position of the lighthouse be 'L'
Given:
When the ship is at the position A, ∠DAL=37°
Now, when the ship sails through a distance of 2.5 i.e at position B
mathematically,
AB=2.5 miles
∠ABL=25°
Now,
∠DAL + ∠LAB = 180°
or
37° + ∠LAB = 180°
or
∠LAB = 180° - 37° = 143°
Also, In ΔLAB
∠LAB + ∠ABL + ∠ALB = 180°
or
143° + 25° + ∠ALB = 180°
or
∠ALB = 180° - 143° - 25° = 12°
Now using the concept of the sin law
In ΔLAB
or
AL = 5.08 miles
and,
or
BL = 7.23 miles
hence,
The distance between the lighthouse and the ship
from the start position A = 5.08 miles
from the Final point B = 7.23 miles
