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V125BC [204]
3 years ago
13

Plz help plz help me will mark brainilest

Chemistry
1 answer:
vovangra [49]3 years ago
8 0

Is it science subject or math

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Does a physical change affect the identity of a substance
Ierofanga [76]
Physical change. Physical changes are changes affecting the form of a chemical substance, but not its chemical composition. ... Physical changes occur when objects or substances undergo a change that does not change their chemical composition.
6 0
4 years ago
When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coeffici
Sergio [31]

<u>Answer:</u> The molecular balanced equation is written below

<u>Explanation:</u>

A molecular equation is defined as the chemical equation in which the ionic compounds are written as molecules rather than component ions.

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the decomposition of bromine trifluoride follows:

2BrF_3\rightarrow Br_2+3F_2

By Stoichiometry of the reaction:

2 moles of bromine trifluoride produces 1 mole of bromine gas and 3 moles of fluorine gas

Hence, the molecular balanced equation is written above.

7 0
3 years ago
____ 26. what is the weight percentage of nitrogen in urea, cn2h4o
Paraphin [41]
Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100

From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams

therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams

Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%
7 0
4 years ago
For a particular reaction, ΔH⁰ = − 46.7 kJ/mol and ΔS⁰ = − 123.8 J / (mol ⋅ K). Assuming these values change very little with te
PilotLPTM [1.2K]

Answer:

T = 377.2 K, Less than

Explanation:

The thermodynamic quantity used in predicting whether a reaction is spontaneous or not is the gibbs free energy.

It's relationship with ΔH⁰ and ΔS⁰ is given as;

ΔG° = ΔH° - TΔS°

Basically, a negative value of ΔG° means the reaction is spontaeneous.

To obtain the calculated vale of T,

ΔS° = ΔH°/T

T = ΔH° / ΔS°

T = 377.2 K

Let's calculate the value of ΔG° at that temperature.

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 377.2(− 123.8)

ΔG°  = 0 (approximately, values are due to the rounding off)

At ΔG°  = 0 the reaction is at equilibrium.

To find if the reaction is spontaneous at lower or hugher temperature than the calculated temperature, we would be substituting the value of T with a smaller (random) value and also a larger (random) value.

Larger T (390K)

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 390(− 123.8)

ΔG°  = - 46700 + 48,282

ΔG° = 1582 J/mol

Smaller T (350K)

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 350(− 123.8)

ΔG°  = - 46700 + 43330

ΔG° = -3370J/mol

This means the temperature would be lesser than the calculated value for it to be spontaneus.

8 0
3 years ago
1. Particles of the solid are<br> and can only
SVEN [57.7K]

Answer:

Closed packet together and they only can vibrate.

Explanation: Solids can have a crystalline or amorphous structure.

7 0
3 years ago
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