How much work is done if 10 N is applied to a 5kg object for 10 meters if there is an opposing force of 5 N
1 answer:
Answer:
50 J
Explanation:
The net force acting on the box is given by the algebraic sum of the two forces, so:
The net work done on the box is equal to (assuming the net force is parallel to the displacement of the object)
where
F = 5 N is the net force on the object
d = 10 m is the displacement of the object
Substituting,
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Answer:
a)
b) a = 19.61[m/s^2]
Explanation:
The total mass of the balloon is:
The buoyancy force acting on the balloon is:
Now we need to make a free body diagram where we can see the forces that are acting over the balloon and determinate the acceleration.
In the attached image we can see the free body diagram and the equation deducted by Newton's second law
