- What is the percent yield if your actual yield is 39.78g and your theoretical
1 answer:
You might be interested in
Answer:
Phosphorus-28 undergoes beta-minus decay to produce
- an electron,
- a Silicon-28 nuclei, and
- an electron antineutrino.
Explanation:
In simple words, when a nucleus undergoes beta-minus decay, a neutron is converted to a proton. An electron and an electron antineutrino will be released.
.
One way to tell whether a neutron is converted to a proton, but not vice versa, is to check the sum charges on the two sides of this equation.
- Left-hand side: 0. Neutron is neutral.
- Right-hand side: 1 + (-1) = 0. Each proton carries a charge of +1. Each electron (beta-minus particle) carries a charge of -1. Antineutrinos are neutral.
The charges on the two sides of this equation is the same. Hence this nuclear equation is possible (but not necessarily correct; however, if the proton and the neutron are in the wrong place the charge won't even be the same.)
Since the mass number of a proton and a neutron are both 1, the overall mass number of the atom will stay the same.
The atomic number is the number of protons in each atom. That number determines the symbol and the chemical properties of the atom. When one neutron in an atom is converted to a proton, the atomic number of the atom will increase by 1.
The atomic number of the daughter nucleus, silicon, is 14. It takes a parent nucleus with atomic number to produce a silicon atom. Refer to a modern periodic table. Atomic number
corresponds to the element aluminum.
Also, the mass number of the daughter nucleus is 28. Since the mass number would stay the same in a beta decay, the mass number of the parent nucleus would also be 28. In other words, it takes an aluminum-28 atom to undergo beta-decay to produce a silicon-28 atom.
Complete the other details (electron and electron antineutrino) to obtain the equation
.
Explanation:
<u>Polar covalent bonding is the type of the chemical bond in which the pair of the electrons is unequally shared between the two atoms.</u> As a result, the atom with higher value of electronegativity acquires a slightly negative charge and the atom with lower value of electronegativity acquires a slightly positive charge.
In the molecule of , the bond which is closest to ionic end of bond spectrum is <u>N-H bond</u> because the nitrogen atom is more electronegative than hydrogen and is ionic in nature.
In the molecule of , the bond which is closest to ionic end of bond spectrum is <u>no one</u> because there is not much difference between carbon and hydrogen for the bond to be said as ionic.
In the molecule of , the bond which is closest to ionic end of bond spectrum is <u>O-H bond</u> because the oxygen atom is more electronegative than hydrogen and is ionic in nature.