·The acceleration of gravity is proportional to
1 / (the square of the distance from the center) .
When we're on the surface, we're 1 radius from the center of the Earth,
and the acceleration of gravity is 9.8 m/s² .
The boy's weight = (mass) · (gravity) = (50kg) · (9.8 m/s²)
= 490 newtons .
At the distance of 5 radii from the center (4 radii altitude from the surface),
the acceleration of gravity is
(9.8 m/s²) · (1/5)² = 0.39 m/s² .
The boy's weight is (mass) · (gravity) = (50kg) · (0.39 m/s²)
= 19.6 newtons .
Just as we expected, his weight at that distance is
(19.6 / 490) = 0.04 = 1/25 = 1/5² of his weight on the surface.
Answer:
0.0334N
Explanation:
Given parameters:
M1 = 5 x 10⁶kg
M2 = 1 x 10⁶kg
Distance = 100m
Unknown:
Gravitational force = ?
Solution:
To solve this problem, we use the Newton's law of universal gravitation.
Fg = 
G is the universal gravitation constant
m is the mass
r is the distance
Fg = 
= 0.0334N
Which of the following pairings are more likely to be held together with the strong nuclear force
Explanation:
1.What does a strong nuclear force do in an atom? It repels electrons from other electrons. It repels protons from other protons. It attracts protons and neutrons.
2.The chain reaction requires both the release of neutrons from fissile isotopes undergoing nuclear fission and the subsequent absorption of some of these neutrons in fissile isotopes.
3.The strong nuclear force holds most ordinary matter together because it confines quarks into hadron particles such as the proton and neutron. In addition, the strong force binds these neutrons and protons to create atomic nuclei.
Answer:
107 °F
Explanation:
Given that
The temperature at sea level = 100°F
height ,h= 2000 feet
The average lapse rate = 3.5°F/1000 feet
Given that rise in temperature 3.5°F per 1000 feet.
1000 feet ⇒ 3.5°F
Given that 2000 feet
2000 feet ⇒ 3.5°F x 2 +100°F
2000 feet ⇒ 107 °F
Therefore the temperature will be 107 °F .
Like a lot of other things, (gravity, sound, electrostatic force), brightness also decreases as the square of the distance.
When the source moves to a new position that's 4 times as far away, its apparent brightness becomes (1/4^2) its original value.
That's 1/16 .
