Using the theorem of kinetic energy
1/2mVf² - 1/2mVi²= WF + Wp, Wp=0
WF = F. AB, AB=5m and F= 40N, m=20kg
so the final kinetic is KEf= 1/2mVf² = WF =<span>F. AB= 40*5=200J
</span>
the final velocity is 1/2mVf² <span>=200, implies Vf= sqrt(20)=2sqrt(5)m/s</span>
The resistance of the cylindrical wire is
.
Here
is the resistance,
is the length of the wire and
is the area of cross section. Since the wire is cylindrical
. Rearranging the above equation,

Here
.
Substituting numerical values,

Te diameter of the wire is 
Answer:
<h2>The answer is 4 s</h2>
Explanation:
The time taken can be found by using the formula

where
d is the distance
v is the velocity
From the question we have

We have the final answer as
<h3>4 s</h3>
Hope this helps you
Answer: I-131, P-32, Sr-90, Co-60 & Technetium.
Explanation: Isotopes like I-131 are used to diagnose goiter in thyroid gland and isotopes like P-32 Sr-90 are used for treatment of skin cancer and Co-60 for cancer and technetium is used to monitor bone growth.