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tia_tia [17]
2 years ago
5

Please help me classify properly.

Chemistry
2 answers:
Grace [21]2 years ago
5 0

Answer:C

Explanation:

Homogeneous Mixture

UkoKoshka [18]2 years ago
3 0

Answer:

homogeneous mixture

Explanation:

it is the same throughout so therefore it can be separated

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ch4aika [34]

Answer: It is a molecular compound. (2) It contains a metal. (3) It can conduct electricity as a solid.

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2 years ago
Why is Mars red? Please describe your answer.
kupik [55]

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the reason why Mars is red is because of its regolith, or surface material, contains lots of iron oxide — the same compound that gives blood and rust their hue

6 0
3 years ago
For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia
Fittoniya [83]

Answer : The value of E^o_{(Cu^{2+}/Cu)} is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction:  Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction:  Cu^{2+}+2e^-\rightarrow Cu

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu

To calculate the E^o_{(Cu^{2+}/Cu)} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}

Putting values in above equation, we get:

1.10V=E^o_{(Cu^{2+}/Cu)}-(-0.76V)

E^o_{(Cu^{2+}/Cu)}=0.34V

Hence, the value of E^o_{(Cu^{2+}/Cu)} is, 0.34 V

8 0
3 years ago
CH3-CH2-CH=CH-CH=CH2
o-na [289]

Answer:

Hydration (of an alkene)

Mechanism : Electrophilic addition.

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