The reaction corresponds to the combustion of propane (C3H8). The balanced reaction is:
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
The reaction enthalpy is given as:
ΔHrxn = ∑nΔH°f(products) - ∑ nΔH°f(reactants)
= [3ΔH°f(CO2(g)) + 4ΔH°f(H2O(g)] - [1ΔH°f(C3H8(g)) + 5ΔH°f(O2(g)]
= [3(-393.5) + 4(-241.8)] - [-103.9 + 5(0)] = -2043.8 kJ
The enthalpy for the combustion of propane is -2044 kJ
Answer: A material that readily transmits energy is a conductor, while one that resists energy transfer is called an insulator .
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Explanation:
You can test by putting sand in one cup and water in another. Then you put the thermometers in the cups. One you have done that you can use the heat lamp and put both cups under it for the same amount of time. After you do that and recorded your data you are done with the experiment.
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☃️ Chemical formulae ➝ 
How to find?
For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

Solution:
❍ Molecular weight of 
= 2 × 126.90
= 253.80
= 254 (approx.)
❍ Given weight: 12.7
Then, no. of moles,
⇛ No. of moles = 12.7 / 254
⇛ No. of moles = 0.05 moles
⚘ No. of moles of Iodine molecule in the given weight = <u>0.05</u><u> </u><u>moles </u>
<u>━━━━━━━━━━━━━━━━━━━━</u>
Given the balanced chemical equation for combustion of propane:

Moles of propane
=3.6 mol
Propane is the limiting reactant as the other reactant oxygen is said to be present in excess.
Amount of products formed would depend on the moles of limiting reactant.
Mole ratio of water to propane as per the balanced chemical equation
=
Calculating the moles of water produced from 3.6 mol propane:


= 14.4mol
Theoretical yield of water = 14.4 mol
Actual yield = 12 mol
Percent yield = 
= 