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ira [324]
3 years ago
12

Most of an atom's volume is found:

Chemistry
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

most of its mass is in the nucleus

Explanation:

the nucleus consists of protons and nutrons

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What is the limiting reactant if 12 moles of p4 react with 15 moles of o2?.
brilliants [131]

Answer:

see explanation

Explanation:

To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.

    P₄      +     5O₂       => 2P₂O₅

12/1 = 12      15/5 = 3

O₂ is the limiting reactant. P₄ will be in excess when rxn stops.

4 0
2 years ago
What element has a half-life = to 64
Virty [35]
The best answer is the isotope of strontium which is strontium-85. It has a half-life of about 64 days. The metal strontioum has four stable, naturally occurring isotopes which includes 84Sr (0.56%), 86Sr (9.86%), 87Sr (7.0%) and 88Sr (82.58%).
5 0
3 years ago
Why is graphite used instead of gold or copper wires to conduct electricity in very hot situations such as an industrial kiln?
olga2289 [7]
<span>The strong bonds give graphite high boiling and melting points, while the weak bonds make graphite soft and flexible.</span>
5 0
3 years ago
Read 2 more answers
I'll give 40 pts for this one but pls help me....
Ivenika [448]
3 of them left and i just need points lol sorrrry
3 0
3 years ago
Vitamin D is produced in the skin when 7-dehydrocholesterol reacts with UVB rays (ultraviolet B) having wavelengths between
goblinko [34]

The energy range expected is 6.6 × 10^-19 J < E < 7.33 × 10^-19 J

The energy of the photon is given by;

E = hc/λ

E = energy of the photon

h = Plank's constant

c = speed of light

λ = wavelength of light

For the upper boundary range;

E = ?

h = 6.6 × 10^-34 Js

c = 3  × 10^8 m/s

λ = 270 × 10^-9

E =  6.6 × 10^-34 Js × 3  × 10^8 m/s / 270 × 10^-9

E = 7.33 × 10^-19 J

For the lower range;

E = ?

h = 6.6 × 10^-34 Js

c = 3  × 10^8 m/s

λ =300 × 10^-9

E =  6.6 × 10^-34 Js × 3  × 10^8 m/s / 300 × 10^-9

E = 6.6 × 10^-19 J

Hence, the energy range 6.6 × 10^-19 J < E <  7.33 × 10^-19 J

Learn more: brainly.com/question/24857760

8 0
2 years ago
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