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3 years ago

How many molecules of Carbon Dioxide (CO2) are there in 2 CO2?

Chemistry

1 answer:

Dima020 [189]3 years ago

5 0

There are 2 molecules of Carbon dioxide(CO2)

<h3>Further explanation</h3>

Given

Molecules of CO2

Required

The number of molecules

Solution

The coefficient of a molecule shows the number of that molecule, while the subscript after the name of the atom indicates the number of that atom in the molecule

Because there is a coefficient of 2 in front of the CO2 molecule, then the number of CO2 molecules is 2

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Building block of all matter is what<br>please help

babunello [35]

Atoms are the building blocks of all matter

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3 years ago

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- Nitinol is an alloy of *

Aleks04 [339]

Answer:

Nickel and Titanium

Explanation:

Nitinol is an alloy of Nickel and Titanium. It posesses two properties such that,

The shape memory effect
Super elasticity

Shape memory is the ability of nitinol to undergo deformation at one temperature, stay in its deformed shape when the external force is removed.

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3 years ago

Balanced nuclear equation forces the alpha decay Po-210

Serjik [45]

Answer:

$_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}$

Explanation:

Your unbalanced nuclear equation is:

$_{84}^{210}\text{Po} \longrightarrow \, _{x}^{y}\text{Z} + \, _{2}^{4}\text{He}$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.

Then

84 = x + 2, so x = 84 - 2 = 82

210 = y + 4, so y = 210 - 4 = 206

Element 82 is lead, so the nuclear equation becomes

$_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}$

8 0

3 years ago

Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.89×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.25×10−4, what is the

Sergio [31]

Answer:

$1.2\times 10^{-2}$

Explanation:

The given reactions are:

PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq) $K_3 = 1.89\times 10^{-10}$

AgCl(aq)⇌Ag+(aq)+Cl−(aq) $K_4 = 1.25\times 10^{-4}$

Required reaction is:

PbCl2(aq)+2Ag+(aq)⇌2AgCl(aq)+Pb2+(aq)

$K_f = \frac{K_3}{K_4^2}\\=\frac{1.89\times 10^{-10}}{1.25\times 10^{-4}}^2\\=1.2\times 10^{-2}$

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3 years ago

A patient needs to be given exactly 1000 ml of a 5.0% (w/v) intravenous glucose solution. the stock solution is 55% (w/v). how m

LiRa [457]

The patient needs 1000 ml of 5% (w/v) glucose solution
i.e 1000 ml x 5 g/ 100 ml
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3 years ago