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Svet_ta [14]
2 years ago
9

A runner starts at position A. He runs 40 m North, 10 m East and 40 m

Physics
1 answer:
Alecsey [184]2 years ago
8 0
The answer is C.) 10 m East
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This is the answer to Question 5

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3 years ago
1.Mention two uses of the concave mirror.
Anuta_ua [19.1K]

Answer:

1. telescope

2.

f =  \frac{r}{2}

f =  \frac{r}{2}f- focal length

f =  \frac{r}{2}f- focal length r- the radius of curvature of the mirror

\frac{1}{f}  =   \frac{1}{p}  +  \frac{1}{l}

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l-the distance of the figure from the vertex of the mirror

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3 years ago
A plane designed for vertical takeoff has a mass of 8.0 × 10³ kg. Find the net work done by all forces on the plane as it accele
artcher [175]

Answer:

<em>the net work done after starting from rest is =  2.4 × 10⁵ J</em>

Explanation:

Work: Work can be defined as the product of force and distance. The fundamental unit of work is Joules (J),  The unit of Energy is Joules (J), as such Energy and work are interchangeable during calculation, This is illustrated below

E = W = 1/2mv².......................... Equation 1

Where m = mass of the plane, v = velocity of the plane, E = Energy, W = work done.

v² = u² + 2as ................................. Equation 2.

Where v = final velocity of the plane, u = initial velocity of the plane, a = acceleration of the plane, distance of the plane.

<em>Given: a = 1.0 m/s², s = 30 m, u = 0 m/s (at rest)</em>

<em>Substituting these values into equation 2</em>

<em>v² = 0² +2×1×30</em>

<em>v² = 60</em>

<em>v = √60</em>

<em>v = 7.75 m/s</em>

Also given: m = 8.0 × 10³ kg, and v = 7.75 m/s

<em>Substituting these values into equation 1,</em>

<em>W = 1/2(8.0×10³)(7.75)²</em>

<em>W = (4.0×10³)(60)</em>

W = 240 × 10³ J

<em>W = 2.4 × 10⁵ J</em>

<em>Therefore the net work done after starting from rest is =  2.4 × 10⁵ J</em>

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3 years ago
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Answer:

200N

Explanation:

0.5/1.5=x/600N

1/3=x/600

x=200N

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The Earth’s internal __________ source provides the energy for our dynamic planet, providing it with the driving force for on-go
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