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irina1246 [14]
3 years ago
6

What are some examples of long term environmental changes???

Chemistry
1 answer:
kolezko [41]3 years ago
3 0

Answer: A long-term environmental change is... ice age, deforestation, urbanization, Earth's orbit, Sun's intensity, global Warming, radioactive waste/pollution. Extinction of species could happen to anyone of the food webs in a long term change.

Explanation:

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Which statement describes the energy changes that occur as bonds are broken and formed during a chemical reaction? 1.Energy is a
Snowcat [4.5K]

Answer:

C

Explanation:

Br + Br-> Br2 (covalent bond)

bond formation releases energy, as the Br's are in a lower energy state like Br2

6 0
3 years ago
Consider the reaction 2CuCl2 + 4K - 2Cul + 4KCI + 12. If 4 moles of CuCl2 react with 4 moles of KI, what is the limiting reactan
Free_Kalibri [48]
Haha i’m trying to do the same one i’ll make sure if i find out how too to get back to you!
8 0
3 years ago
A 100.0 mL solution containing 0.864 g of maleic acid (MW=116.072 g/mol) is titrated with 0.276 M KOH. Calculate the pH of the s
Lilit [14]

Answer:

pH = 1.32

Explanation:

                 H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺

This problem involves a weak diprotic acid which we can solve by realizing they amount  to buffer solutions.  In the first  deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:

So first calculate the moles reacted and produced:

n H₂M = 0.864 g/mol x 1 mol/ 116.072 g  =  0.074 mol H₂M

54 mL x  1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH

it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.

moles H₂M left = 0.074 - 0.015 = 0.059

moles HM⁻ produced = 0.015

Using the Henderson - Hasselbach equation to solve for pH:

ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325

Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.

For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.

           

3 0
3 years ago
Element A has a half-life of 10 days. A scientist measures out 200 g of this substance. After 30 days has passed, the scientist
myrzilka [38]
N=N₀*2^(-t/T)

N₀=200 g
T=10 d
t=30 d

N=200*2^(-30/10)=25 g

25 g will remain
4 0
3 years ago
Read 2 more answers
14. As the temperature of the reaction is increased,
AfilCa [17]
Reactant molecules collide more frequently and with greater energy per collision
3 0
3 years ago
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