Answer:
The force constant of the spring is 11.11 N/m.
Explanation:
Given;
mechanical energy of the oscillation, E = 0.005 J
amplitude of the oscillation, A = 0.03 m
maximum speed of the glider, V = 0.145 m/s
Energy is conserved in simple harmonic motion, the total mechanical energy is given as;
E = ¹/₂kA²
Where;
A is the amplitude of the oscillation
k is the force constant
Make k the subject of the formula, from the equation above;
kA² = 2E
k = 2E / A²
k = (2 x 0.005) / (0.03²)
k = 11.11 N/m
Therefore, the force constant of the spring is 11.11 N/m.
