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Tpy6a [65]
3 years ago
6

The shortening of a transmitted signal's wavelength and/or an increase in its frequency, which indicates that the object is

Physics
1 answer:
Mrrafil [7]3 years ago
7 0

Answer: The Doppler effect occurs when a source of a wave is moving relative to an observer (or the observer is moving relative to the source). In this case, the apparent frequency of the sound, as heard/seen by the observer, is shifted with respect to the original frequency of the wave.

More specifically, the relationship between the apparent frequency, f', and the original frequency, f, is given by:

where:

is the velocity of the wave

is the velocity of the observer relative to the source, and it is positive if the observer is moving towards the source, and negative if the observer is moving away from the source

is the velocity of the source relative to the observer, and it is positive if the source is moving away from the observer, and negative if the source is moving towards the observer

The doppler effect occurs in many daily-life situations: for instance, when an ambulance approaches you, you hear an increase in the apparent frequency of the siren due to the Doppler effect. Another example is the movements of distant galaxies from us: when they move away from us, the apparent frequency of the light they emit decreases, so their wavelengths appear to increase towards the red color (red-shift); on the contrary, when they are moving towards us, the apparent frequency seems to increase, so the wavelength seems to decrease towards the blue color (blue-shift).

Explanation:

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Gravitational potential energy equals mass*gravity*height At the starting level her gpe is 0 At2.5m below plg in 2.5 for height
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1. The matter a wave travels through is called a
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It is called a medium
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A spring hangs from the ceiling. A mass of 0.50 kg is attached to the end of the spring which then oscillates with simple harmon
Marina CMI [18]

Answer:

46.77N/m

Explanation:

to find the spring constant you can use the following formula:

T=2\pi\sqrt{\frac{m}{k}}

T: period of oscillation = 0.65s

m: mass of the object = 0.50kg

By doing k the subject of the formula and replacing you obtain:

k=4\pi^2\frac{m}{T^2}=4\pi^2\frac{0.50kg}{(0.65s)^2}=46.72\frac{N}{m}

hence, the spring constant is 46.77N/m

5 0
4 years ago
Read 2 more answers
A record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.60 m/s2 for 11.0 s. 2
Aleks [24]

Answer:

x_total = 4662.5 m

Explanation:

This is a one-dimensional math problem, we must find the displacement in each section and then add them together.

1) let's use the equation

       x = v₀ t + ½ a t²

where it indicates that part of rest for which v₀ = 0

       x₁ = ½ a₁ t²

       x₁ = ½ 2.60 11²

       x₁ = 157.3 m

2) The second displacement is at constant speed,

   let's find the final speed of the previous displacement

       v = v₀ + a₁ t₁

       v = a₁ t₁

       v = 2.60 11

       v = 28.6 m / s

now we use the uniform speed

      v = x₂ / t₂

      x₂ = v t₂

let's reduce the time to SI units

      t₂ = 2.60 min (60 s / 1min) = 156 s

      x₂ = 28.6  156

      x₂ = 4461.6 m

3) it is braking

       x₃ = v t₃ - ½ a₃ t₃²

       x₃ = 28.6 3.05 - ½ 9.38 3.05²

        x₃ = 43.60m

a) total displacement is the sum of each displacement

     x_total = x₁ + x₂ + x₃

     x_total = 157.3 + 4461.6 + 43.60

     x_total = 4662.5 m

4 0
4 years ago
An overhead transmission line is 6.2 m above the ground. The magnetic field due to the transmission line at a point on the groun
Serjik [45]

Answer:

I = 837 A

Explanation:

  • The magnetic field due to the current flowing along a very long wire, at a distance r from the center of the wire, can be written as follows:

       B= \frac{\mu_{0}*I}{2*\pi*r}

  • where μ₀ = 4*π*10⁻⁷ N/A², B = 0.27 G = 0.27*10⁻⁴ T, r = 6.2 m
  • We can solve for the current I, as follows:

        I = \frac{2*\pi*r*B}{\mu_{0}} = \frac{B*r}{2e-7} =\\ I = \frac{0.27e-4T*6.2m}{(2e-7)N/A2} = 837 A

  • The current flowing through the wire is 837 A.
8 0
3 years ago
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