Ans; see attached file for calculation and answer
Explanation:
 
        
             
        
        
        
Answer:
w = 5832.372 Joules
Explanation:
Mass of water, m = 20 kg
The water was pulled up to a height of 35 meters, i.e. h = 35 m
It takes 14 minutes to pull up the water through the height, 35 m
speed = distance/ time = 35/14 = 2.5 m/min
The bucket's height, y = speed * time = 2.5t meters
6 kg of water drips out of the bucket throughout the 14 minutes
The rate at which the water drips drips out = (6/14) = 0.4286 kg/min
Mass of water that drips out in time, t = 0.4286t kg
The mass of water remaining = (20 - 0.4286t) kg
Change in Workdone, Δw = mgΔy
 Δy = 2.5 Δt 
 Δw = mg *  2.5 Δt 
 dw =  (20 - 0.4286t)g2.5 dt
integrating both sides
dw = (50g - 1.07gt)dt
 where b = 0, a = 14
 where b = 0, a = 14
w = 50gt - 1.07g(t²)/2      g = 9.8 m/s²
w = 490t - 5.243t²
w = (490*14 - 5.243*14²) - (490*0 - 5.243*0²)
w = 6860 - 1027.628
w = 5832.372 Joules
 
        
             
        
        
        
The answer is a. Hope this helps :)
        
                    
             
        
        
        
Answer:
Since in summer, the eastern side do not face the sunlight and hence the water in eastern pot remain cool in summer.