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3 years ago

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A package is dropped from an airplane flying at an altitude of 69.2 m with a velocity of 1.40 x 10^2 km/h. Calculate the horizon

tal distance that the package lands from the lane.

1 answer:

Andrew [12]3 years ago

5 0

69.2 m with a velocity of 1.40* 10^2 km/h.

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It may seem dangerous to be in a car during a thunderstorm, but it's actually relatively safe. Since the car is essentially a me

balu736 [363]

Answer:

The charges from the thunderstorm flow through the conductive metal

of which the vehicle is made and distribute themselves on the outside surface of the vehicle

Explanation:

It is actually safer to stay inside a car during a thunderstorm rather than standing outside the car. The reason is this, thunder passes electrical charges through a conductor. The body of the vehicle is made of a metal which is a good conductor of electricity. The charges will redistribute themselves on the body of the vehicle (a metallic conductor of electricity) hence the occupants of the car are relatively safe.

The reasons described above makes those inside the vehicle relatively safe compared to a person standing outside.

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3 years ago

Read 2 more answers

By using electroscope, if the body is negatively charged then due to electrostatic induction, then on the leaves there will be a

Kryger [21]

(b) negative charge

This is the answer

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3 years ago

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A 51.0 kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 10.0 m th

shepuryov [24]

Answer:

The final speed of the crate is 12.07 m/s.

Explanation:

For the first 10.0 meters, the only force acting on the crate is 225 N, so we can calculate the acceleration as follows:

$F = ma$

$a = \frac{F}{m} = \frac{225 N}{51.0 kg} = 4.41 m/s^{2}$

Now, we can calculate the final speed of the crate at the end of 10.0 m:

$v_{f}^{2} = v_{0}^{2} + 2ad_{1}$

$v_{f} = \sqrt{0 + 2*4.41 m/s^{2}*10.0 m} = 9.39 m/s$

For the next 10.5 meters we have frictional force:

$F - F_{\mu} = ma$

$F - \mu mg = ma$

So, the acceleration is:

$a = \frac{F - \mu mg}{m} = \frac{225 N - 0.17*51.0 kg*9.81 m/s^{2}}{51.0 kg} = 2.74 m/s^{2}$

The final speed of the crate at the end of 10.0 m will be the initial speed of the following 10.5 meters, so:

$v_{f}^{2} = v_{0}^{2} + 2ad_{2}$

$v_{f} = \sqrt{(9.39 m/s)^{2} + 2*2.74 m/s^{2}*10.5 m} = 12.07 m/s$

Therefore, the final speed of the crate after being pulled these 20.5 meters is 12.07 m/s.

I hope it helps you!

7 0

3 years ago

Use a common denominator to find-2/3 + -4/5

Juliette [100K]

Answer:

-22/15

Explanation:

the least common denominator is 15 so first you multiply -2/3 by 5 in both the numerator and denominator making it -10/15

Then you do the same to -4/5 except you multiply the numerator and denominator by 3 giving you -12/15

If you add -10/15+ -12/15 you get -22/15

6 0

3 years ago

Una motocicleta viaja con una velocidad constante de 72m/s calcula su velocidad en km/h

Juliette [100K]

Answer:

Entonces la velocidad de la motocicleta es $259.18 \frac{km}{h}$

Explanation:

La regla de tres simple es una operación que ayuda a resolver rápidamente problemas de proporcionalidad, teniendo tres valores conocidos y una incógnita.

Dos magnitudes son directamente proporcionales cuando al multiplicar o dividir una de ellas por un número, la otra queda multiplicada o dividida respectivamente por el mismo número. En otras palabras, dos magnitudes son directamente proporcionales si cuando aumenta una magnitud, también lo hace la otra en la misma proporción o cuando disminuye una magnitud, también lo hace la otra en la misma proporción.

Para resolver una regla directa de tres cuando las magnitudes son directamente proporcionales, se debe seguir la siguiente fórmula:

a ⇒ b

c ⇒ x

Entonces $x=\frac{c*b}{a}$

La regla directa de tres simple es la regla que se aplica en este caso donde hay un cambio de unidades. Para realizar esta conversión de unidades, primero debe saber que 1 m = 0.001 km. Entonces, si 0.001 km es 1 m, ¿cuántos kilómetros son 72 m?

$km=\frac{72 m*0.001 km}{1 m}$

km=0.072

Entonces:

$72\frac{m}{s} =\frac{72 m}{s} =\frac{0.072 km}{s}$

Siendo 1 s=0.0002778 h:

$72\frac{m}{s} =\frac{72 m}{s} =\frac{0.072 km}{s}=\frac{0.072 km}{0.0002778 h}=259.18 \frac{km}{h}$

<u><em>Entonces la velocidad de la motocicleta es </em></u> $259.18 \frac{km}{h}$ <u><em></em></u>

8 0

3 years ago