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asambeis [7]
3 years ago
14

Calculate the amount of heat lost by 23 g of water when its temperature drops from 68.0°C to 31.0°C. The specific heat of water

is 4.18 J/(g°C).
Chemistry
1 answer:
34kurt3 years ago
8 0

Answer:

3557J is the heat lost by the water

Explanation:

Using the equation:

Q = m*C*ΔT

<em>Where Q is change in heat</em>

<em>m is mass of substance (23g of water)</em>

<em>C is specific heat of the substance (4.18J/g°C)</em>

<em>And ΔT is change in temperature (68.0°C - 31.0°C = 37.0°C)</em>

<em />

we can find the amount of heat lost as follows:

Q = 23g*4.18J/g°C*37°C

Q =

3557J is the heat lost by the water

<em />

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