C.) Mitochondria is the answer...
<span>Lifting an object increases the gravitational potential energy of the system. If you release the object, that potential energy will be transformed into the energy of an object in motion which is termed as the kinetic energy as it falls toward earth. Hope this helps.</span>
Answer:
or ![1.9532799844\times 10^{12}g](https://tex.z-dn.net/?f=1.9532799844%5Ctimes%2010%5E%7B12%7Dg)
23.4843749996 m
Yes
Explanation:
E = Electric field = ![2\times 10^5\ N/C](https://tex.z-dn.net/?f=2%5Ctimes%2010%5E5%5C%20N%2FC)
c = Speed of light = ![3\times 10^8\ m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8%5C%20m%2Fs)
m = Mass of proton= ![1.67\times 10^{-27}\ kg](https://tex.z-dn.net/?f=1.67%5Ctimes%2010%5E%7B-27%7D%5C%20kg)
q = Charge of electron = ![1.6\times 10^{-19}\ C](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C)
Acceleration is given by
![a=\dfrac{Eq}{m}\\\Rightarrow a=\dfrac{2\times 10^5\times 1.6\times 10^{-19}}{1.67\times 10^{-27}}\\\Rightarrow a=1.9161676647\times 10^{13}\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BEq%7D%7Bm%7D%5C%5C%5CRightarrow%20a%3D%5Cdfrac%7B2%5Ctimes%2010%5E5%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%7D%7B1.67%5Ctimes%2010%5E%7B-27%7D%7D%5C%5C%5CRightarrow%20a%3D1.9161676647%5Ctimes%2010%5E%7B13%7D%5C%20m%2Fs%5E2)
Dividing by g
![\dfrac{a}{g}=\dfrac{1.9161676647\times 10^{13}}{9.81}\\\Rightarrow a=1.9532799844\times 10^{12}g](https://tex.z-dn.net/?f=%5Cdfrac%7Ba%7D%7Bg%7D%3D%5Cdfrac%7B1.9161676647%5Ctimes%2010%5E%7B13%7D%7D%7B9.81%7D%5C%5C%5CRightarrow%20a%3D1.9532799844%5Ctimes%2010%5E%7B12%7Dg)
The acceleration is
or ![1.9532799844\times 10^{12}g](https://tex.z-dn.net/?f=1.9532799844%5Ctimes%2010%5E%7B12%7Dg)
![v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{(0.1\times 3\times 10^8)^2-0^2}{2\times 1.9161676647\times 10^{13}}\\\Rightarrow s=23.4843749996\ m](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20s%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2a%7D%5C%5C%5CRightarrow%20s%3D%5Cdfrac%7B%280.1%5Ctimes%203%5Ctimes%2010%5E8%29%5E2-0%5E2%7D%7B2%5Ctimes%201.9161676647%5Ctimes%2010%5E%7B13%7D%7D%5C%5C%5CRightarrow%20s%3D23.4843749996%5C%20m)
The distance is 23.4843749996 m
The gravitational field is very small compared to the electric field so the effects of gravity can be ignored.
Answer:
the Earth magnetic field in that region is about 89.09
T
Explanation:
If the magnetic field has an inclination of
, and its horizontal component is 17 microTesla, then we can calculate the magnitude of the full magnetic field via the cosine function. Notice that the decomposition of a vector in horizontal and perpendicular components originates a right angle triangle where the vector is the hypotenuse of the triangle.
![cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(79^o)=\frac{17}{B} \\B=\frac{17}{cos(79^o)}\,\mu T \\B=89.09\,\,\mu T](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D%5C%5Ccos%2879%5Eo%29%3D%5Cfrac%7B17%7D%7BB%7D%20%5C%5CB%3D%5Cfrac%7B17%7D%7Bcos%2879%5Eo%29%7D%5C%2C%5Cmu%20T%20%20%5C%5CB%3D89.09%5C%2C%5C%2C%5Cmu%20T)
Answer:
The ball will be overtake superman after travelled distance 248.5 m.
Explanation:
Given that,
Speed of superman = 35 m/s
Height = 330 m
Mass of ball = 10 kg
Let the height at which they are at same position be S.
For superman,
We need to calculate the time
Using equation of motion
...(I)
For ball,
![S=u't+\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=S%3Du%27t%2B%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
From equation (I) and (II)
![ut=u't+\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=ut%3Du%27t%2B%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
![ut=0+\dfrac{1}{2}\times g\times t^2](https://tex.z-dn.net/?f=ut%3D0%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20g%5Ctimes%20t%5E2)
![u=\dfrac{1}{2}\times g\times t](https://tex.z-dn.net/?f=u%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20g%5Ctimes%20t)
![t=\dfrac{2u}{g}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B2u%7D%7Bg%7D)
Put the value into the formula
![t=\dfrac{2\times35}{9.8}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B2%5Ctimes35%7D%7B9.8%7D)
![t=7.1\ sec](https://tex.z-dn.net/?f=t%3D7.1%5C%20sec)
We need to calculate the distance travelled
Using formula of distance
![d=v\times t](https://tex.z-dn.net/?f=d%3Dv%5Ctimes%20t)
Put the value into the formula
![d=35\times 7.1](https://tex.z-dn.net/?f=d%3D35%5Ctimes%207.1)
![d=248.5\ m](https://tex.z-dn.net/?f=d%3D248.5%5C%20m)
Hence, The ball will be overtake superman after travelled distance 248.5 m.