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Marrrta [24]
3 years ago
12

How quickly would a 60kg object accelerate if the person applied a 500N force?

Physics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

acceleration =

8.33ms {}^{ - 2}

Explanation:

we know,

force = mass × acceleration

  • 500 = 60 × a
  • a = 500 / 60
  • a = 50 / 6
  • a = 8.33 m/s^2
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The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

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initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

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Learn more on momentum here: brainly.com/question/402617

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3 years ago
The basic barometer can be used to measure the height of a building. If the barometric readings at the top and the bottom of a b
erma4kov [3.2K]

Answer:

h = 269.6 m

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P_{bottom} = 755 mm Hg

now we will have

(755 \times 10^{-3})(13.6 \times 10^3)(9.81) = P_{bottom}

P_{bottom} = 1.007 \times 10^5 Pa

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P_{top} = 0.974 \times 10^5

now we have

(1.007 - 0.974)\times 10^5 = 1.25 (9.81) h

h = 269.6 m

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3 years ago
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4 years ago
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Temperature. The other three dont have anything to do with determining climate

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3 years ago
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What is the significance of a standard system of measurement?
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Because scientists all over the world are working together, looking for answers to the same questions, just as much as if they all worked in the same physical laboratory in the same building.  They need a way to share data and experimental results in a form that everyone can understand. ( D )

Let's say I perform an experiment and get very exciting results. I'm a good scientist, so the next thing I want to do is to publish a complete description of how I did my experiment, and include all of my results.  That way, scientists around the world can read about what I did, they can find any mistakes that I made, and they can even repeat my experiment for themselves and see if they get the same results.

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3 years ago
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