Answer:
( a ) The specific volume by ideal gas equation = 0.02632 ![\frac{m^{3} }{kg}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B3%7D%20%7D%7Bkg%7D)
% Error = 20.75 %
(b) The value of specific volume From the generalized compressibility chart = 0.0142 ![\frac{m^{3} }{kg}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B3%7D%20%7D%7Bkg%7D)
% Error = - 34.85 %
Explanation:
Pressure = 1 M pa
Temperature = 50 °c = 323 K
Gas constant ( R ) for refrigerant = 81.49 ![\frac{J}{kg k}](https://tex.z-dn.net/?f=%5Cfrac%7BJ%7D%7Bkg%20k%7D)
(a). From ideal gas equation P V = m R T ---------- (1)
⇒
= ![\frac{R T}{P}](https://tex.z-dn.net/?f=%5Cfrac%7BR%20T%7D%7BP%7D)
⇒ Here
= Specific volume = v
⇒ v = ![\frac{R T}{P}](https://tex.z-dn.net/?f=%5Cfrac%7BR%20T%7D%7BP%7D)
Put all the values in the above formula we get
⇒ v =
×81.49
⇒ v = 0.02632 ![\frac{m^{3} }{kg}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B3%7D%20%7D%7Bkg%7D)
This is the specific volume by ideal gas equation.
Actual value = 0.021796 ![\frac{m^{3} }{kg}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B3%7D%20%7D%7Bkg%7D)
Error = 0.02632 - 0.021796 = 0.004524 ![\frac{m^{3} }{kg}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B3%7D%20%7D%7Bkg%7D)
% Error =
× 100
% Error = 20.75 %
(b). From the generalized compressibility chart the value of specific volume
= v = 0.0142 ![\frac{m^{3} }{kg}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B3%7D%20%7D%7Bkg%7D)
The actual value = 0.021796 ![\frac{m^{3} }{kg}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B3%7D%20%7D%7Bkg%7D)
Error = 0.0142 - 0.021796 = ![\frac{m^{3} }{kg}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B3%7D%20%7D%7Bkg%7D)
% Error =
× 100
% Error = - 34.85 %
Answer:
Explanation:
The fact is that there exists no temperature change until a phase change is complete. That is to say, during a phase change, the energy that will be supplied is used only to separate the molecules. There is no part of it is used to increase the kinetic energy of the molecules. So its temperature will not rise, not really, since the kinetic energy of the molecules remains the same. Also, it should be noted that the average kinetic energy of the molecules does not change at the moment that melting occurs, thus the temperature of the molecules does not change.
D = 318 meters
vi = 0 m/s
vf =????
a = 9.81
Formula
=======
vf^2 = vi^2 + 2*a*d
Substitute and solve.
================
vf^2 = 0^2 + 2 * 9.81 * 318
vf^2 = 6239.16
v = sqrt(6239.16)
v = 78.990 m/s I guess down is minus in your classroom.
Anyway pick -79 <<<<<=======
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Answer: The work done is W = 3528J.
Explanation: Work (W) is an amount of energy used to do determined movement. To calculate it, we use the formula, as the movement is horizontal:
W = F.d, where
F is force on the object
d is distance it went through.
The force acting on the crate is due to friction.
= μ . ![F_{N}](https://tex.z-dn.net/?f=F_%7BN%7D)
μ is the kinetic friction
is the normal force
There is no up and down movement, so
, with g = 9.8m/s²
= μ . m . g
= 0.9 . 80 . 9.8
= 705.6 N
Substituing
into the work formula, we have:
W =
. d
W = 705.6 . 5
W = 3528 J
The work done to move the crate across a distance of 5m is 3528 J.