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Harlamova29_29 [7]
3 years ago
8

In the solar system, the distribution of light and heavy elements is as follows: Group of answer choices Most of the light and h

eavy elements are within a few astronomical units of the center. Within a few astronomical units of the center, most of the matter consists of light elements. Beyond that, most of the matter consists of heavy elements. Most of the light and heavy elements are generally farther than a few astronomical units from the center. Within a few astronomical units of the center, most of the matter consists of heavy elements. Beyond that, most of the matter consists of light elements.
Physics
1 answer:
Liula [17]3 years ago
6 0

Answer:

Most of the light and heavy elements are within a few astronomical units of the center.  

Explanation:

The solar system is composed of different celestial bodies that are called small or large bodies, which revolve around the sun, all of these bodies are the elements of the solar system, which in addition to having different sizes, have different densities and weights from each other . One thing these elements have in common, regardless of their weight, that most of them have astronomical units of the center, which are units of length generated from the average distance from the Earth to the Sun.

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The answer is C 100 km/h west
5 0
3 years ago
I need a short answer ?
mars1129 [50]

Answer:

Explanation:

7a) t = d/v = 100/45cos14.5 = 2.29533...= 2.30 s

7b) h = ½(9.81)(2.29533/2)² = 6.46056... = 6.45 m

  or

  h = (45sin14.5)² / (2(9.81)) = 6.47 m

which rounds to the same 6.5 m when limiting to the two significant digits of the initial velocity.

7 0
3 years ago
A 40kg rock falls off a cliff that is 50 meters high. How fast is the speed of the rock when it hits the ground
Oksi-84 [34.3K]

31.3m/s

Explanation:

Given parameters:

Mass of rock = 40kg

Height of cliff = 50m

Unknown:

Speed of rock when it hits ground = ?

Solution:

We are going to use the appropriate motion equation to solve this problem

The rock is falling with the aid of gravitational force. The force is causing it to accelerate with an amount of velocity.

  Using;

                      V²  = U² + 2gH

V = unknown velocity

U = initial velocity = O

g = acceleration due to gravity = 9.8m/s²

H = height of fall

since the initial velocity of the bodyg is 0

     V²  = 2gH

    V= √2gH = √2 x 9.8 x 50 = 31.3m/s

learn more:

Velocity brainly.com/question/4460262

#learnwithBrainly

7 0
4 years ago
A student pushes a box with a total mass of 50 kg. What is the net force on the box if it accelerates 1.5 m/s
Harrizon [31]
We now that follow newton rules f=ma so net force equal to mass*acceleration=>f=50*1.5=75 N
3 0
3 years ago
Read 2 more answers
A speeder passes a parked police car at a constant speed of 23.3 m/s. At that instant, the police car starts from rest with a un
KonstantinChe [14]

Answer:

32s

Explanation:

We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:

x=vt=23.3\frac{m}{s}t

and the police car distance:

x=vt+\frac{at^{2}}{2}=0+\frac{2.75\frac{m}{s^{2}} t^{2}}{2}=0.73\frac{m}{s^{2}}

Since they both travel the same distance x, we can equal both formulas and solve for t:

0 = 0.73\frac{m}{s^{2}}t^{2}-23.3\frac{m}{s} t\\\\0=t(0.73\frac{m}{s^{2}}t-23.3\frac{m}{s} )\\\\

Two solutions exist to the equation; the first one being t=0

The second solution will be:

0.73\frac{m}{s^{2}}t=23.3\frac{m}{s}\\\\t=\frac{23.3\frac{m}{s}}{0.73\frac{m}{s^{2}}}=32s

This result allows us to confirm that the police car will take 32s to catch up to the speeder

7 0
3 years ago
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