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3 years ago

Mechanical advantage = load/_______

Chemistry

2 answers:

arlik [135]3 years ago

8 0

Answer:

Mechanical advantage = load/<u>effort</u>

Explanation:

Mechanical advantage is like a ratio of load to effort and many machines like pulleys depend on this relationship between load and effort for it to work.

agasfer [191]3 years ago

6 0

Answer:

The formula of mechanical advantage is Load÷effort

Explanation:

Mechanical advantage is the ratio of the load to the effort i.e. MA=Load(L)÷Effort(E)

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snow_lady [41]

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2 years ago

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What is the density of an object with a mass of 140 g and a volume<br> of 6 ml

Strike441 [17]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{140}{6} = \frac{70}{3} \\ = 23.3333...$

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3 years ago

Is the equation for reaction 1 balanced? Explain your reasoning. If the reaction is not balanced, then state how you would balan

sveticcg [70]

Answer:

Reaction is already balanced

Explanation:

The equation in reaction 1 is given as;

CH3COOH + NaHCO3 --> CO2 + H2O + Na+ + CH3COO-

The reaction is already balanced. This is because the umber of atoms of elements in the reactant is equal to that of the products

Carbon

Reactant = 2 + 1 = 3

Product = 2 + 2 = 3

Hydrogen

Reactant = 3 + 1 + 1 = 5

Product = 2 + 3 = 5

Oxygen

Reactant = 2 + 3 = 5

Product = 2 +1 + 2 = 5

Sodium

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3 0

3 years ago

What is the instantaneous rate of formation of product C given the following information: a. Stoichiometric equation A+ B2C+ D b

quester [9]

Answer:

1.728 mol /(L*min)

Explanation:

Hello,

In the attached photo, you'll find the numerical procedure for your question.

- Take into account that the negative sign is eligible for reagents and positive for products.

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6 0

3 years ago

A sample of pure NH4HS is placed in a sealed 2.0-L container and heated to 550 K at which the equilibrium constant is 3.5 x 10-3

Zolol [24]

Answer:

The mass of $NH_{3}$ in the container is 2.074 gram

Explanation:

Given:

Volume of $NH_{4} HS$ $V = 2$ lit

Equilibrium constant $k _{eq} = 3.5 \times 10^{-3}$

The reaction in which $NH_{3}$ is produced

$NH_{4} HS$ ⇄ $NH_{3} + H_{2}S$

Here equal moles of $NH_{3}$ and $H_{2}S$ is formed.

From the formula of equilibrium constant,

$k_{eq} = (NH_{3})(H_{2}S )$

$x^{2} = 3.5 \times 10^{-3}$

$x = 0.061$ M

Above value shows,

$NH_{3} = 0.061$ $\frac{moles}{L}$

So in 2 L no. moles of $NH_{3}$ = $0.061 \times 2 = 0.122$ moles.

So mass of 0.122 mole of $NH_{3}$ is = $0.122 \times 17 = 2.074$ g

Therefore, the mass of $NH_{3}$ in the container is 2.074 gram

8 0

3 years ago

Mechanical advantage = load/_______​

Mechanical advantage = load/_______