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2 years ago

What would happen if the oceanic plates stoped moving

Chemistry

2 answers:

loris [4]2 years ago

8 0

Answer:All life would die!!

Explanation:The Earth's oceans and continents would no longer exist if the plates stopped moving. Everything would dry up and flatten out. The atmosphere would build up CO2 and could become uncomfortably hot and difficult to breathe.

Ket [755]2 years ago

3 0

Answer:

But without plate tectonics, Earth will simply stop making new ones. The mountains we have now would erode over a few million years, turning into low, rolling hills. Our planet would eventually flatten out, with more land ending up underwater. On the bright side, there'd be fewer natural disasters.

Explanation:

that is what would happen

You might be interested in

What happens when an atom of sulfur combines with two atoms of chlorine to produce SCl2?

RoseWind [281]

Answer:

Each chlorine atom shares a pair of electrons with the sulfur atom. ... Each chlorine atom shares all its valence electrons with the sulfur atom

8 0

3 years ago

How many moles of CO are there in 1.40 x 10^24 molecules.

viva [34]

Answer:

Explanation:

Mole = no. Molecules/6.02×10^23

Mole = (1.40×10^24)/(6.02×10^23)

Mole = 2.33mole

6 0

3 years ago

When the temperature of a rigid hollow sphere containing 685 L of helium gas is held at 621 K, the pressure of the gas is 1.89 x

Leno4ka [110]

You have to use the equation PV=nRT.
P=pressure (in this case 1.89x10^3 kPa which equals 18.35677 atm)
1V=volume (in this case 685L)
n=moles (in this case the unknown)
R=gas constant (0.08206 (L atm)/(mol K))
T=temperature (in this case 621 K)
with the given information you can rewrite the ideal gas law equation as n=PV/RT.
n=(18.35677atm x 685L)/(0.08206atmL/molK x 621K)
n=246.8 moles

8 0

2 years ago

The combustion of ethene in the presence of excess oxygen yields carbon dioxide and water: c2h4 (g) + 3o2 (g) → 2co2 (g) + 2h2o

meriva

Answer:

$\boxed{-267.5}$

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

$\Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}$

The equation for the reaction is

C₂H₄(g) + 3O₂(g) ⟶ 2CO₂(g) + 2H₂O(ℓ)

ΔS°/J·K⁻¹mol⁻¹ 219.5 205.0 213.6 69.9

$\Delta_{r} S^{\circ} = (2\times213.6 + 2\times69.9) - (1\times219.5 + 3\times205.0)\\\\= 567.0 - 834.5 = \boxed{-267.5 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}}$

3 0

3 years ago

How do I solve this problem?

JulijaS [17]

First question. Applying ideal gas equation PV=nRT, P= 101.3 x 10³Pa = 1atm. therefore, 1 x 260 x 10^-3 = n x 0.082 x 294.( Temperature in kelvin=273+21). n = 0.01 moles. Volume of gas at STP= n x 22.4 = 0.01x22.4 = 0.224L. Hope this helps

5 0

2 years ago