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uysha [10]
3 years ago
5

11. A bowling ball has a mass of 7 kg and a velocity of 3 m/s. (A) What is the ball's momentum?

Physics
1 answer:
DaniilM [7]3 years ago
7 0

Answer: 21 kg x m/s

Momentum can be found using the equation p = mv, or momentum = mass times velocity.

Therefore, to find the momentum of the bowling bowl, you can plug the mass and velocity values into the equation to get p = (7kg)(3m/s)

Solve the equation to get a momentum of 21kg x m/s

I hope I could help :)

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Please help!
andrew-mc [135]

Answer:

V=W/Q

107V= W/17C

= We= 107×17 J

= 1819 J

Explanation:

hope it helps

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3 years ago
1. . The maximum current output of a 60 Ω circuit is 11 A. What is the rms voltage of the circuit?
natta225 [31]

Answer:In a DC circuit, the power consumed is simply the product of the DC voltage times the DC current, given in watts.for AC circuits with reactive components we have to calculate the consumed power differently.

a 1/4 watt resistor or a 20 watt amplifier.

3 0
3 years ago
Assume that the same amount of current passes through the electromagnets shown. Identify which electromagnet is stronger than th
hodyreva [135]

First electromagnet

Explanation:

The first electromagnet is the strongest and it is stronger than the given electromagnet above.

An electromagnet is a temporary magnet made by passing current through a wire wounded round an iron core or metallic core.

  • When current is passed through, the metal becomes magnetic.
  • The strength of the electromagnet depends on the number of coil round the metal core and also the intensity of current passed through it.
  • The higher the number of coils wounded round the metal core, the stronger the electromagnet that will be produced.
  • Also, the higher the intensity of electricity passed through the wire, the stronger it is.

learn more:

Electromagnet brainly.com/question/2191993

#learnwithBrainly

3 0
3 years ago
Read 2 more answers
13. Now we will examine the electric field of a dipole. The magnitude and direction of the electric field depends on the distanc
Gennadij [26K]

This question is incomplete, the complete question is;

Now we will examine the electric field of a dipole. The magnitude and direction of the electric field depends on the distance and the direction. We will investigate in detail just two directions. With charges available in the simulation (all the charges are either positive or negative 1 nC increments).

how do you create a dipole with dipole moment 1 x 10-9 Cm with a direction for the dipole moment pointing to the right. Make a table below that shows the amounts of  charge and the distance between the charges. There are many correct answers

Answer:

Given the data in question;

Dipole moment P = 1 × 10⁻⁹ C.m

now dipole pointing to the right;

               P→

_{-\theta } (-) ---------------->(+) _{+\theta }

               d

so let distance between the dipoles be d

∴ P = d\Theta

Let \Theta_{1} = 1 nC

so

P = d\Theta

1 × 10⁻⁹ =  1 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (1 × 10⁻⁹)

d = 1 m

Also Let \Theta_{2} = 2 nC

so

P = d\Theta

1 × 10⁻⁹ =  2 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (2 × 10⁻⁹)  

d = 0.5 m

Also Let \Theta_{3} = 3 nC

so

P = d\Theta

1 × 10⁻⁹ =  3 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (3 × 10⁻⁹)

d = 0.33 m

such that;

charge                 distance

1 nC                        1.00 m      

2 nC                       0.50 m

3 nc                        0.33 m

4 nC                       0.25 m

5 nC                       0.20 m      

5 0
3 years ago
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