Convert 162 km/h into m/s.

Which statement below best describes the quantum view of light and matter?

poizon [28]

The correct option is D.
The Quantum theory states that both light and matter are made up of small particles that possess wavelike and particle like properties. This is described as the dual nature of light and matter. Light is made up of photons while matter is made up of electron, proton and neutron. The two can behave as both waves and particles.

6 0

3 years ago

What are the factor that affect gravity

valentinak56 [21]

Explanation:

The factors that affect gravity are as follows:

1. mass of body

2. acceleration

Keep smiling and hope u are satisfied with my answer.Have a good day :)

6 0

3 years ago

Constants Modern wind turbines are larger than they appear, and despite their apparently lazy motion, the speed of the blades ti

nadezda [96]

It is given that the length of blade of the turbine is 58 m.

During the motion, the turbine will undergo rotational motion. Hence the radius of the circle traced by the turbine is equal to the length of the blade.

Hence radius r = 58 m.

The frequency of the turbine [f] =14 rpm.

Here rpm stands for rotation per minute.

Hence the frequency of the turbine in one second-

$f=\frac{14}{60}\ s^-1$

$f=0.23333 Hz$

Here Hz[ hertz] is the unit of frequency.

The angular velocity of the turbine $\omega =2\pi f$

$\omega=2*3.14*0.2333$

$\omega=1.465124$ radian/second

Now we have to calculate the centripetal acceleration of the blade.

Let the linear velocity of the blade is v.

we know that linear velocity v=ωr

The centripetal acceleration is calculated as-

$a_{c} =\frac{v^2}{r}$

$=\frac{[\omega r]^2}{r}$

$=\omega^2r$

$=[1.465124]^2 *58$

$=124.5021234 m/s^2$ [ans]

8 0

3 years ago

An ant walks 2\,\text m2m2, start text, m, end text to the right and then climbs 1 \,\text m1m1, start text, m, end text up a wa

NNADVOKAT [17]

Answer:

26.56°

Explanation:

given,

horizontal distance travel by the ant = 2 m

vertical distance travel by the ant = 1 m

angle of the ant above the initial point = ?

using trigonometric function

$tan \theta = \dfrac{h}{x}$

θ is the angle of the ant form initial position

h is the height on the wall

x is the horizontal distance covered by the ant

$tan \theta = \dfrac{1}{2}$

$\theta =tan^{-1}(0.5)$

$\theta =26.56^0$

hence, the angle made by the ant from the initial position is equal to 26.56°

3 0

3 years ago

Between this and the next assignment, we want to get a better under- standing of how light interacts with the eye. Here are two

STatiana [176]

Answer:

θ₁ = 3.35 10⁻⁴ rad , θ₂ = 8.39 10⁻⁵ rad

Explanation:

This is a diffraction problem for a slit that is described by the expression

sin θ = m λ

the resolution is obtained from the angle between the central maximum and the first minimum corresponding to m = 1

sin θ = λ / a

as in these experiments the angle is very small we can approximate the sine to its angle

θ = λ / a

In this case, the circular openings are explicit, so the system must be solved in polar coordinates, which introduces a numerical constant.

θ = 1.22 λ / D

where D is the diameter of the opening

let's apply this expression to our case

indicates that the wavelength is λ = 550 nm = 550 10⁻⁹ m

the case of a lot of light D = 2 mm = 2 10⁻³ m

θ₁ = 1.22 550 10-9 / 2 10⁻³

θ₁ = 3.35 10⁻⁴ rad

For the low light case D = 8 mm = 8 10⁻³

θ₂ = 1.22 550 10-9 / 8 10⁻³

θ₂ = 8.39 10⁻⁵ rad

5 0

3 years ago