Question

How much NaAlO2 (sodium aluminate) is required to produce 2.15 kg of Na3AlF6?

Answer 1

Answer:

839 g

Explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.

M_r:              81.97                209.94

                   NaAlO₂ + … ⟶ Na₃AlF₆ + …

Mass/g:                                   2150

1. Calculate the moles of Na₃AlF₆

Moles of Na₃AlF₆ = 2150 × 1/209.94       Do the operation

Moles of Na₃AlF₆ = 10.24 mol Na₃AlF₆

2. Calculate the moles of NaAlO₂

The molar ratio is 1 mol NaAlO₂:1 mol Na₃AlF₆

Moles of NaAlO₂ = 10.24 × 1/1 = 10.24 mol NaAlO₂

3. Calculate the mass of NaAlO₂

Mass of NaAlO₂ = 10.24 × 81.97             Do the multiplication

Mass of NaAlO₂ = 839 g