Answer:
W = 12 kJ
Explanation:
We have,
Voltage of a battery is 12 V
Charge supplied by the battery is 1000 C
It is assumed to find the work is done by the battery in moving the charge. The work done is given in terms of voltage as :
or
W = 12 kJ
So, the work of 12 kJ is done by battery in moving charges.
Answer:
To find the mass using density and volume we just multiply them against each other which causes ml to cancel and just leaves us with grams which represents how much the item weights.
Therefore, our final answer is that our pencil weight 3.5 grams
<u><em>Hope this helps! Let me know if you have any questions</em></u>
Answer:
5.60 m/s
Explanation:
His initial potential energy is equal to his final kinetic energy.
mgh = 1/2mv^2
2gh = v^2 . . . . . . . multiply by 2/m
v = √(2gh) = √(2(9.81 m/s²)(1.6 m)) = √(31.392 m²/s²)
v ≈ 5.60 m/s
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<em>Additional comment</em>
The mass is irrelevant in the equations we typically use for this purpose.
Answer:
the balls reached a height of 4.9985 m
Explanation:
Given the data in the question;
mass one m = 3.8 kg
mass two M = 2.1 kg
Initial velocities
u = 22 m/s
U = { moving downward} = 12 m/s
Now, using the law conservation of linear moment;
mu + MU = v( m + M )
we solve for "v" which is the velocity of the ball s after collision;
v = (mu + MU) / ( m + M )
so we substitute our given values into the equation
v = ( ( 3.8 × 22 ) + ( 2.1 × -12) ) / ( 3.8 + 2.1 )
v = ( 83.6 - 25.2 ) / 5.9
v = 58.4 / 5.9
v = 9.898 m/s
Now, we determine required height using the following relation;
v"² - v² = 2gh
where v" is the velocity at the top which is 0 m/s and g = -9.8 m/s²
0 - v² = 2gh
v² = -2gh
so we substitute
( 9.898 )² = -2 × -9.8 × h
97.97 = 19.6 × h
h = 97.97 / 19.6
h = 4.9985 m
Therefore, the balls reached a height of 4.9985 m
Explanation:
The area between the speed-time graph f a body and time axis measures the distance travelled by the body