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aliina [53]
3 years ago
13

What does the amplitude of a light wave determine?

Physics
2 answers:
Illusion [34]3 years ago
8 0
The amplitude of a wave is a measure of the displacement of the wave from its rest position. The amplitude is also a measure of the strength or intensity of the wave e.g the loudness
Hope this helps :)
Andrew [12]3 years ago
6 0
The amplitude of a wave tells us about the intensity or brightness of the light relative to other light waves of the same wavelength.
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Using organisms such as fungi to detoxify a polluted area is called
Levart [38]

Answer:

bioremediation :)

Explanation:

7 0
3 years ago
4. The blades on a fan have a frequency of 15 Hz.
vichka [17]

Answer:

a) 4500 cycles b) 0.0667s c) 6.67s

Explanation:

a) 15 Hz= 15 cycles/ s

   5 mins= 300s

   15 cycles/s * 300s= 4500 cycles

b) Period= 1/ frequency

   Period= 1/ 15 cycles/s

   Period= 0.0667s

c) Period * number of revolutions= time

  0.0667 * 100= 6.67s

6 0
4 years ago
On a frictionless track,cart 1 is moving with a constant,rightward(+) velocity of 1.0m/s.Cart 2 is also moving rightward with co
mamaluj [8]

Answer:

The final velocity of cart 1 is 3m/s

Explanation:

From principle of conservation of linear momentum, which states that sum of the momentum before collision is equal to the sum of the momentum after collision.

Momentum, P is given as mass x velocity.

ΔP = Δmv = m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂

Assumptions:

  • If the two carts are moving on frictionless track, then limiting frictional forces due to their weights are negligible.
  • After the elastic collision, the two carts will move separately with different velocity

u₁ + u₂ = v₁ + v₂;

where;

u₁ and u₂  are the initial velocity for cart 1 and cart 2 respectively

v₁ and v₂  are the final velocity for cart 1 and cart 2 respectively

1 m/s + 5 m/s = v₁  + 3m/s

6 m/s =  v₁  + 3m/s

v₁  = 6 m/s - 3m/s = 3m/s

Therefore, the final velocity of cart 1 is 3m/s

4 0
3 years ago
Rate in miles/hours if your run at a speed 2.2 20miles
Vinvika [58]
9.1 miles per hour because 2.2 is your hours right?
5 0
4 years ago
The absolute temperature of a sample of monatomic ideal gas is doubled at constant volume. What effect
Advocard [28]
<h3><u>Answer;</u></h3>

Doubles and Remains the same

<h3><u>Explanation;</u></h3>
  • The effect of doubling the absolute temperature of a sample of a monoatomic ideal gas is that,the pressure doubles and density of the sample of gas remains the same.
  • <em><u>According to ideal gas equation; PV = nRT; Where P is pressure and V is the Volume, n is the number of moles, R is the ideal gas constant and T is the absolute temperature.</u></em>
  • <em><u>Therefore, when the temperature of the mono atomic ideal gas is doubled, the pressure of the gas will also doubles.</u></em>
  • However, in a closed chamber mass of the ideal gas is invariant, since density depends only on the mass and volume therefore the density of the ideal is gas will remain the same.
5 0
3 years ago
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