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romanna [79]
2 years ago
6

Can you plz help me??

Physics
1 answer:
Vlad [161]2 years ago
6 0
Im pretty sure it C broskie i might be wrong but im pretty sure
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A piece of wood is floating in a bathtub. A second piece of wood sits on top of the first piece, and does not touch the water. I
Mashutka [201]

Answer:

the water level remains same

Explanation:

This can be explained by Archimedes's principle which says that the wood will sink if weight of wood is more than the weight of the water displaced with weight equal to the water displaced otherwise the wood will float.

Therefore, buoyancy or the buoyant force is the same as the weight of wood, the weight of the water displaced by wood is also the same as that of the weight of wood.

Thus, we can see that the weight of the wood remains same and so is the level of water.

6 0
2 years ago
Velocity is a vector quantity because...
statuscvo [17]
It has both magnitude and direction
5 0
2 years ago
Please help me :Find the resultant of two forces of 1.5N and 2.0N at 90 degrees to each other, with the 1.5N force acting vertic
Roman55 [17]

Answer:

resultant force = (f1²+f2²)½

=(1.5²+2²)½

=(2.25+4)½

=(6.25)½

=2.5

Explanation:

okay this question seems easy. now if the 1.5 is vertically upwards so is that 2 is horizontally downwards hence as u say its 90 degrees thn it forms a right angled triangle.

4 0
2 years ago
Approximately where is it currently high tide on Earth? Group of answer choices wherever it is currently noon anywhere that ocea
Wewaii [24]

Answer:

Option D, only on the portion of the Earth facing directly toward the Moon

Explanation:

Tides are caused by the gravitational pull of moon. The part of earth that faces the moon experiences the highest gravitational force and hence the high tides will occur in this regions only. The regions that do not faces the moon experiences low tides. It is the gravity of moon that attracts the ocean water towards itself.

Hence, Option D is correct

7 0
2 years ago
If it requires 2.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re
valina [46]

Answer:

16 J

Explanation:

It is given that,

Work done, W = 2 J

A spring is stretched by 2.0 cm from its equilibrium length

We need to find how much more work will be required to stretch it an additional 4.0 cm.

Let k is the spring constant of the spring. When W = 2J, and x = 2 cm, then energy required to stretch the spring is :

U=\dfrac{1}{2}kx^2\\\\k=\dfrac{2U}{x^2}\\\\k=\dfrac{2(2)}{(0.02)^2}\\\\k=10000\ N/m

The energy required to stretch the spring from 2 cm to additional 4 cm i.e. 2+4= 6 cm.

W=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 10000\times ((0.06)^2-(0.02)^2)\\\\W=16\ J

So, the required work done is 16 J.

7 0
3 years ago
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