Question

IF 14.07*10^26 molecules of magnesium chloride was produced in the following reaction, how many grams of magnesium reacted?

Answer 1

Answer:

56160grams

Explanation:

First, we need to convert the number of molecules of magnesium chloride (MgCl2) into moles by dividing by Avagadro's number (6.02 × 10^23 molecules)

n = nA ÷ 6.02 × 10^23

n = 14.07 × 10^26 ÷ 6.02 × 10^23

n = 14.07/6.02 × 10^(26-23)

n = 2.34 × 10^3 moles of MgCl2

The balanced reaction given in the question is as follows:

Mg + 2HCl → MgCl2 + H2

If 1 mole of Mg produced 1 mole of MgCl2

Then, 2.34 × 10^3 moles of Mg will also produce 2.34 × 10^3 moles of MgCl2.

Using mole = mass ÷ molar mass (MM)

Molar mass of Mg = 24g/mol

mass = mole × MM

mass = 2.34 × 10^3 × 24

mass = 56.16 × 10^3

mass = 56160grams.