There's not enough information in the question to calculate the answer.
Knowing the child's walking speed, we would need to know how often s/he takes a step in order to calculate the length of their legs.
ΔVl = L di/dt
i = i₀e -t/T
di/dt = i₀ × (-1/T) e -t/T
ΔVl = L× (-I/T i₀e -t/T
ΔVl = -L/T i₀e -t/T
b. 15mm, i₀ = 36mA, T = 1.1m
t= Os
ΔVl = 0,491V
C. t = 1ms
ΔVl = 0.198V
t = 2ms
ΔVl = 0.08V
E. t = ms
ΔVl = 0.032V
Complete Question
A voltaic cell is constructed with two 
electrodes. The two cell compartment have ![[Zn^{2+}] = 1.6 \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D%20%3D%20%201.6%20%5C%20M)
and ![[Zn^{2+}] = 2.00*10^{-2} \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D%20%3D%20%202.00%2A10%5E%7B-2%7D%20%5C%20%20M)
respectively.
What is the cell emf for the concentrations given? Express your answer using two significant figures
Answer:
The value is 
Explanation:
Generally from the question we are told that
The concentration of ![[Zn^{2+}]](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D)
at the cathode is ![[Zn^{2+}]_a = 1.6 \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D_a%20%3D%20%201.6%20%5C%20M)
The concentration of at the anode is ![[Zn^{2+}]_c = 2.00*10^{-2} \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D_c%20%3D%20%202.00%2A10%5E%7B-2%7D%20%5C%20%20M)
Generally the the cell emf for the concentration is mathematically represented as
![E = E^o - \frac{0.0591}{2} log\frac{[Zn^{2+}]a}{ [Zn^{2+}]c}](https://tex.z-dn.net/?f=E%20%3D%20%20E%5Eo%20-%20%5Cfrac%7B0.0591%7D%7B2%7D%20log%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5Da%7D%7B%20%5BZn%5E%7B2%2B%7D%5Dc%7D)
Generally the 
is the standard emf of a cell, the value is 0 V
So
![E = 0 - \frac{0.0591}{2} * log[\frac{ 2.00*10^{-2}}{1.6} ]](https://tex.z-dn.net/?f=E%20%3D%20%200%20%20-%20%20%5Cfrac%7B0.0591%7D%7B2%7D%20%20%2A%20log%5B%5Cfrac%7B%202.00%2A10%5E%7B-2%7D%7D%7B1.6%7D%20%5D)
=>
B. a combustion reaction involves a hydrocarbon burning with oxygen gas to produce water and carbon dioxide.
C. this is an endothermic reaction since ΔH would be positive.
3. I am pretty sure it is referring to the activation energy which is a characteristic all chemical reaction have and in a combustion reaction the spark gets the reaction over the activation energy.
4. K₂O(s)+CO₂(g)⇒K₂CO₃(s)+energy
The energy level of the reactants is higher than the energy level of the products (you can see this with energy diagrams).
5. 2HgO(s)+energy⇒2Hg(l)+O₂(g)
the energy levels of the products is higher than the energy level of the reactants. (this can also be seen with energy diagrams)
