Answer:
104.969 amu.
Explanation:
From the question given above, the following data were obtained:
Isotope A:
Mass of A = 107.977 amu
Abundance (A%) = 0.1620%
Isotope B:
Mass of B = 106.976 amu
Abundance (B%) = 1.568%
Isotope C:
Mass of C = 105.974 amu
Abundance (C%) = 47.14%
Isotope D:
Mass of D = 103.973 amu
Abundance (D%) = 51.13%
Average atomic mass =?
The average atomic mass of the element can be obtained as follow:
Average atomic mass = [(Mass of A × A%) /100] + [(Mass of B × B%) /100] + [(Mass of C × C%) /100] + [(Mass of D × D%) /100]
Average atomic mass = [(107.977 × 0.1620)/100] + [(106.976 × 1.568)/100] + [(105.974 × 47.14)/100] + [(103.973 × 51.13)/100]
= 0.175 + 1.677 + 49.956 + 53.161
= 104.969 amu
Therefore, the average atomic mass of the element is 104.969 amu.
Catalyst can speed up chemical reaction without being used up or involved in thr reaction..
Explanation:
cant answer without context
Answer: The moles of carbon needed will be, 13.8 moles
Explanation: Moles of = 5.52 mole
Now we have to calculate to moles of carbon.
The given balanced chemical reaction is,
From the balanced chemical reaction, we conclude that
As, 2 mole of react to give 5 moles of carbon
So, 5.52 mole of react to give moles of carbon
Therefore, the moles of carbon needed will be, 13.8 moles
