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3 years ago

Static___ sliding rolling_ fluid_____

Physics

2 answers:

Arisa [49]3 years ago

6 0

Answer:

a car

A sled sliding across snow or ice.

a ball down a hill

mercury

Explanation:

Phantasy [73]3 years ago

3 0

Static reaction

Sliding down a water slide

Rolling down a hill

Fluids running down a pipe

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WILL GIVE BRAINLIEST

Vladimir [108]

Answer:

$2\:\mathrm{m/s^2}$

From Newton's 2nd Law, we have $\Sigma F=ma$ . Substituting given values, we have:

$40=20a,\\a=\frac{40}{20}=\boxed{2\:\mathrm{m/s^2}}$

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3 years ago

A mass with mass 4 is attached to a spring with spring constant 24 and a dashpot giving a damping 20. The mass is set in motion

aleksandrvk [35]

Answer: $x(t) = 14e^{-2t} - 10e^{-3t}$

Explanation: In a mass-spring-damper system, the differential equation that rules the motion of the mass is: mx" + cx' + kx = 0

Using m = 4, k = 24 and c = 20, we have

4x" + 20x' + 24x = 0

Simplifying, we have

x" + 5x'+ 6x = 0

The characteristic equation of this differential is

$r^{2} + 5r + 6 = 0$

The solutions for the quadratic equation are: $r_{1} = -2$ and $r_{2} = -3$

Hence:

x(t) = $C_{1}e^{-2t} + C_{2}e^{-3t}$

x'(t) = $-2C_{1}E^{-2t} - 3C_{2}e^{-3t}$

To determine the constants, we have the initial conditions x(0) = 4 and

x'(0) = 2, then:

$x(0) = C_{1} + C_{2} = 4\\ C_{1} = 4 - C_{2}$

$x'(0) = -2C_{1} -3C_{2} = 2\\-2(4-C_{2}) -3C_{2} = 2\\C_{2} = -10\\C_{1} = 4 - C_{2}\\C_{1} = 14$

Substituing the constants:

$x(t) = 14e^{-2t} - 10e^{-3t}$

The position function for this system is: $x(t) = 14e^{-2t} - 10e^{-3t}$

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3 years ago

Static_______ sliding______ rolling_______ fluid_________

Static___ sliding rolling_ fluid_____