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2 years ago

Which statement best explains the speed of light waves as a travel from a gas to a solid

Physics

1 answer:

Natalija [7]2 years ago

3 0

Answer: Light waves slow down as they travel from gas to solid.

Explanation: Light waves move fastest through gases but when going through solids, it moves much slower.

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Help asapp!!!!!!!!!!!!!!

IRINA_888 [86]

Sorry don’t know this one

3 0

2 years ago

6. question is in the picture

Harlamova29_29 [7]

The answer is c you got to look for answers that make sense

8 0

3 years ago

A closely wound search coil has an area of 3.21 cm2, 120 turns, and a resistance of 58.7 O. It is connected to a charge-measurin

Alexxx [7]

Answer:

The magnetic field in the System is 0.095T

Explanation:

To solve the exercise it is necessary to use the concepts related to Faraday's Law, magnetic flux and ohm's law.

By Faraday's law we know that

$\epsilon = \frac{NBA}{t}$

Where,

$\epsilon =$ electromotive force

N = Number of loops

B = Magnetic field

A = Area

t= Time

For Ohm's law we now that,

V = IR

Where,

I = Current

R = Resistance

V = Voltage (Same that the electromotive force at this case)

In this system we have that the resistance in series of coil and charge measuring device is given by,

$R = R_c + R_d$

And that the current can be expressed as function of charge and time, then

$I = \frac{q}{t}$

Equation Faraday's law and Ohm's law we have,

$V = \epsilon$

$IR = \frac{NBA}{t}$

$(\frac{q}{t})(R_c+R_d) = \frac{NBA}{t}$

Re-arrange for Magnetic Field B, we have

$B = \frac{q(R_c+R_d)}{NA}$

Our values are given as,

$R_c = 58.7\Omega$

$R_d = 45.5\Omega$

$N = 120$

$q = 3.53*10^{-5}C$

$A = 3.21cm^2 = 3.21*10^{-4}m^2$

Replacing,

$B = \frac{(3.53*10^{-5})(58.7+45.5)}{120*3.21*10^{-4}}$

$B = 0.095T$

Therefore the magnetic field in the System is 0.095T

3 0

3 years ago

What are the magnitude and direction of the acceleration of an electron at a point where the electric field has magnitude 6100 n

Hoochie [10]

Force on electron due to electric field is given by

$F = eE$

$F = 1.6 * 10^{-19}* 6100$

$F = 9.76 * 10^{-16} N$

now the acceleration is given by

$a = \frac{F}{m}$

$a = \frac{9.76 * 10^{-16}}{9.1 * 10^{-31}}$

$a = 1.07 * 10^{15} m/s^2$

so above is the magnitude of acceleration and its direction is opposite to field as electron is negatively charged so direction is towards SOUTH

4 0

3 years ago

Suppose we repeat the experiment from the video, but this time we use a rocket three times as massive as the one in the video, a

shusha [124]

Answer:

2/3

Explanation:

In the case shown above, the result 2/3 is directly related to the fact that the speed of the rocket is proportional to the ratio between the mass of the fluid and the mass of the rocket.

In the case shown in the question above, the momentum will happen due to the influence of the fluid that is in the rocket, which is proportional to the mass and speed of the same rocket. If we consider the constant speed, this will result in an increase in the momentum of the fluid. Based on this and considering that rocket and fluid has momentum in opposite directions we can make the following calculation:

Rocket speed = rocket momentum / rocket mass.

As we saw in the question above, the mass of the rocket is three times greater than that of the rocket in the video. For this reason, we can conclude that the calculation should be done with the rocket in its initial state and another calculation with its final state:

Initial state: Speed = rocket momentum / rocket mass.

Final state: Speed = 2 rocket momentum / 3 rocket mass. -------------> 2/3

8 0

2 years ago