Answer:
2.25 %
Explanation:
65-95-99.7 is a rule to remember the precentages that lies around the mean.
at the range of mean () plus or minus one standard deviation (),
at the range of mean plus or minus two standard deviation,
at the range of mean plus or minus three standard deviation,
So, note that they are asking about the probability that it is greater than 0.32, that is the mean (0.3) plus two times the standard deviation (0.1) ()
So we know that the 95.5% is between and , hence approximately the 4.5% (100%-95.5%) is greater than 0.32 or less than 0.28. But half (4.5%/2=2.25%) is greater than 0.32 and the other half is less than 0.28.
So
Answer:
From what I know they postponed the movies that were suppose to come out.
Tangential acceleration of a point on the rim of the flywheel during this spin-up process is 0.2548 m/s².
Tangential acceleration is defined as the rate of change of tangential velocity of the matter in the circular path.
Given,
Radius of flywheel (r) = 1.96 cm = 0.0196m
Angular acceleration (α)= 13.0 rad/s²
The tangential acceleration formula is at=rα
where, α is the angular acceleration, and r is the radius of the circle.
using the formula; at=rα = (13.0 rad/s²) (0.0196m) = 0.2548 m/s².
The tangential acceleration is 0.2548 m/s².
Learn more about the Tangential acceleration with the help of the following link:
brainly.com/question/15743294
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<span>The x component of velocity is 9.0m/s, y component is zero initially.</span><span>a = -9.8m/</span><span>s2</span>
Since the jumper lands at a -45-degree angle the final Vy must have the same magnitude as the final Vx. <span>V<span>f2 </span>= V<span>02 </span>+ 2ad</span>Plugging in values:<span>(−9.0m/s<span>)2</span>=0m/s+2(−9.8m/<span>s2</span>)d</span><span>The height difference,d is equal to |-4.13| or 4.13 m.</span>
P = m * v
P = 100 * 5 Kg-m/s towards south
P = 500 Kg-m/s towards south
In short, your answer would be 500 Kg-m/s towards south
Hope this helps!