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3 years ago

How do the hydrosphere and atmosphere interact? give an example

Chemistry

1 answer:

vladimir1956 [14]3 years ago

3 0

Answer:

Evaporation

Explanation:

Water in the ocean, rivers, lakes, etc. is part of the hydrosphere, and when that water evaporates it enters the atmosphere

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As atoms get smaller,valance electrons are getting closer or farther away from the nucleous.The force of attraction is stronger

LiRa [457]

Explanation:

Electrons are closer to the nucleus are in filled orbitals and are called core electrons. More energy which in nucleus called nuclear strOng energy to remove electron thars why its also a way harder too..

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2 years ago

Select the correct structure that

Leto [7]

Answer:

c) both

Explanation:

hey, could you check the question once because I suppose it's 2-hexyne when there's a triple bond and 2-hexene when there's a double bond between Carbon atoms. As of the question asked, it's c) both but it's 2-hexene due to presence of double bond between Carbon atoms.

do tell me as well. have a good day :-))

6 0

3 years ago

What is the best definition for the atomic number in an element

arlik [135]

The atomic number in an element is usually how many protons the element has. For example, Hydrogen has a 1 on top of the H (on the periodic table), therefore, Hydrogen has 1 proton. Oxygen has an 8 on top of the O (on the periodic table) so therefore, Oxygen has 8 protons.

7 0

3 years ago

If this container of gas is heated,

iogann1982 [59]

Answer:

theory

Explanation:

kinetic theory of gases

5 0

3 years ago

Read 2 more answers

How many grams of material is lost in the aqueous phase if two extractions are carried out on 100 mL of a 5% (m/v) aqueous solut

san4es73 [151]

Answer:

4.94g of material

Explanation:

Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:

Kp = 8 = Concentration in Ethyl acetate / Concentration in water

100mL of a 5% solution contains 5g of material in 100mL of water. Thus:

8 = X / 100mL / (5g-X) / 100mL

Where X is the amount of material in grams that comes to the organic phase.

8 = X / 100mL / (5g-X) / 100mL

8 = 100X / (500-100X)

4000 - 800X = 100X

4000 = 900X

4.44g = X

Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.

And will remain 5g-4.44g = 0.56g.

In the second extraction:

8 = X / 100mL / (0.56g-X) / 100mL

8 = 100X / (56-100X)

448 - 800X = 100X

448 = 900X

0.50g = X

In the second extraction, you will extract 0.50g of material

Thus, after the two extraction you will lost:

4.44g + 0.50g = 4.94g of material

6 0

3 years ago