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Katarina [22]
3 years ago
5

Se llena un recipiente con el mismo número de moles de oxígeno y dióxido de carbono. ¿Cuál de las siguientes proposiciones es la

correcta?
Seleccione una:
A. Las moléculas de CO2 tienen la misma energía cinética media que las de O2
B. Las moléculas de CO2 tienen mayor velocidad media de colisión con las paredes del recipiente que las de O2
C. Las moléculas de CO2 tienen mayor velocidad media que las de O2.
D. Las moléculas de CO2 tienen la misma velocidad media que las de O2.
Chemistry
1 answer:
Ronch [10]3 years ago
5 0

Answer:

D. Las moléculas de CO2 tienen la misma velocidad promedio que las moléculas de O2. es la respuesta correcta

Explanation:

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Tsunamis are caused by seismic waves
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4 years ago
What is the most likely charge on an ion formed by an element with a valence electron configuration of ns2np4
Andreas93 [3]

Answer:

2-

Explanation:

For an element to be stable, it must follow the octet rule: an atom will gain, lose or share electrons until its valence shell is complete with 8 electrons.

An element with the valence electron configuration ns²np⁴ has 6 (2+4) electrons in its valence shell. Thus, in order to fulfill the octet, it will gain 2 electrons. As a consequence, it will form an anion with charge 2-.

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How many molecules of O2 are required to react with 3.00 moles P4?<br> P4+5O2⟶2P2O5
likoan [24]

Answer:

1400

Explanation:

8 0
4 years ago
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CaCo3+2HCL Cacl2+h2o+co2
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Answer:

Here

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6 0
3 years ago
If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated
Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution

\Delta T^o = freezing point of water

i = Van't Hoff factor

K_f = freezing point constant

m = molality

w_b = mass of solute

w_a = mass of solvent

M_b = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

6 0
3 years ago
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