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irinina [24]
2 years ago
11

Need help please... thank u​

Physics
2 answers:
Lady_Fox [76]2 years ago
5 0

Answer:

Entirely horizontal

Explanation:

The ball begins the movement with horizontal and vertical velocity, but it is subject to the gravity acceleration, that will break the movement. When it achieves the top of the path, is when the vertical velocity go to 0 and begin to grow in the opposite direction, so in the very top of the path, the velocity is entirely horizontal

tangare [24]2 years ago
4 0

Answer:

the answer from my side is both vertical and horizontal

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Serga [27]

Answer:

\boxed{p =  {7.4 \times 10}^{2} W} \to \: option \: c.

Explanation:

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6 0
2 years ago
You shoot an arrow into the air. Two seconds later (2.00 s) the arrow has gone straight upward to a height of 35.0 m above its l
sdas [7]

This question can be solved by using the equations of motion.

a) The initial speed of the arrow is was "9.81 m/s".

b) It took the arrow "1.13 s" to reach a height of 17.5 m.

a)

We will use the second equation of motion to find out the initial speed of the arrow.

h= v_it + \frac{1}{2}gt^2\\

where,

vi = initial speed = ?

h = height = 35 m

t = time interval = 2 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

35\ m = (v_i)(2\ s)+\frac{1}{2}(9.81\ m/s^2)(2\ s)^2\\\\v_i(2\ s)=19.62\ m\\\\v_i = \frac{19.62\ m}{2\ s}

<u>vi =  9.81 m/s</u>

b)

To find the time taken by the arrow to reach 17.5 m, we will use the second equation of motion again.

h= v_it + \frac{1}{2}gt^2\\

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 17.5 m

vi = initial speed = 9.81 m/s

t = time = ?

Therefore,

17.5 = (9.81)t+\frac{1}{2}(9.81)t^2\\4.905t^2+9.81t-17.5=0

solving this quadratic equation using the quadratic formula, we get:

t = -3.13 s (OR) t = 1.13 s

Since time can not have a negative value.

Therefore,

<u>t = 1.13 s</u>

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

4 0
2 years ago
Which of the following are single-displacement reactions?
ololo11 [35]

Answer:

A & D

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From the options, only options A & D fits this definition of single-displacement reactions.

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The other options are not correct because they don't involve only and element and a compound on each side of the reaction.

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salantis [7]
Hello Micu212006 


Question: <span> Both the large loose rocks and the small loose rocks used to be part of earth's solid rock layer
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Answer: True


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Here's link to the answer:

tinyurl.com/wpazsebu

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2 years ago
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