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Digiron [165]
3 years ago
6

Why is fuel-cell technology, in its present state, not a pollution-free

Chemistry
1 answer:
Brut [27]3 years ago
7 0

Answer:

lol don't know please don't report me

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50 POINTS.
Vladimir79 [104]

#1. The correct answer is A.

#2. The correct answer is

      -A.  Minimum Viable Population (MVP)

      -B.  Increase.

      -C. Death rate decreases.

#3. The correct answer is B.

#4. The correct answer is B.

#5. The correct answer is:

-A. Decrease.

-B. Decrease.

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-D. Decrease.

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Hope this helps ya!! (:

7 0
4 years ago
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What is an Atomic Model
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the structure of an atom, theoretically consisting of a positively charged nucleus surrounded and neutralized by negatively charged electrons revolving in orbits at varying distances from the nucleus, the constitution of the nucleus and the arrangement of the electrons differing with various chemical elements.

Explanation:

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3 years ago
How can crossing over lead to the expression Of new traits
Kamila [148]

Answer:

Crossing over, or recombination, is the exchange of chromosome segments between nonsister chromatids in meiosis. Crossing over creates new combinations of genes in the gametes that are not found in either parent, contributing to genetic diversity.

Explanation:

8 0
4 years ago
Which is one way that topographic maps are different from other maps?
anzhelika [568]
One way they are different is that they show elevation
5 0
3 years ago
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The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihyd
kenny6666 [7]

Answer:

The answer is "= 0.078 \ kg \ H_2".

Explanation:

calculating the moles in CH_4 =\frac{PV}{RT}

                                                =\frac{(0.58 \ atm) \times (923 \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(232^{\circ} C +273)}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(505)K}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (41.4605 \frac{L \cdot atm}{mol})}\\\\= 12.9 \ mol

Eqution:

CH_4 +H_2O \to  3H_2+ CO \ (g)

Calculating the amount of H_2 produced:

= 12.9 \ mol CH_4 \times  \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2

So, the amount of dihydrogen produced = 0.078 \frac{kg}{s}

5 0
3 years ago
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