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Novay_Z [31]
3 years ago
9

A ball is thrown vertically up ward with a velocity of 25m/s. a/how fast was it moving after 2sec?​

Physics
1 answer:
Shalnov [3]3 years ago
3 0

Answer:

12.5

Explanation:

given

distance=25

time=2sec

required

=speed

solution

=v=s/t

25/2

=12.5m/s

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Which option would it be
bekas [8.4K]
This is my notes from last year my teacher really dumbed it down for us lol and it really helped but I'm not so sure if ur question would be answer with this but ik it will help with other problems for Physics I just thought I would share it I hope this helps have a lovely nite and good luck with this question let me know if the pics are good or not!

6 0
4 years ago
1A.)A railroad car of mass 21700 kg moving with a speed of 3.36 m/s collides
Pepsi [2]

Answer:

(a) 2.03 m/s

(b) 2.15 m/s

Explanation:

(a)

From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum

Momentum, p=mv where m is the mass and v is the velocity

m_1v_1+m_2v_2=(m_1+m_2)v_c where v_c is the common velocity, v_1 and v_2 are velocities of the first railroad car  and the second railroad car respectively, m_1 and m_2 are masses of the first railroad car  and the second railroad car respectively

Substituting the given figures then

21700\times 3.36+41700\times 1.34=(21700+41700)v_c\\63400v_c=128790\\v_c=\frac {128790}{63400}=2.031388013\approx 2.03 m/s

(b)

Momentum, p=mv where m is the mass and v is the velocity

m_1v_1+m_2v_2=m_1v_3+m_2v_4 where v_1 and v_2 are initial velocities of the ball moving towards west and the other ball moving in opposite direction respectively, m_1 and m_2 are masses of the first railroad car  and the second railroad car respectively

Taking west as positive then the opposite direction will be negative hence

0.455\times 7.36+(1.01\times -12.4)= 0.455\times -15.4 + (1.01\times v_4}

Note that when the 0.455 rebounds, it moves towards East and since we took West as positive that is why we give 15.4 as a negative value.

-2.1682=1.01v_4\\v_4=\frac {-2.1682}{1.01}=-2.146732673\approx 2.15 m/s towards East

8 0
4 years ago
How to calculate the velocity? the answer is 5.4 m/s I need the explication
Vanyuwa [196]

Answer: sq. root of .735

Explanation:

multiply two on both sides.

(2) *2,94 = (0,200 * v^2) (2)

588 = 0400 * 2v^2

divide by 400 on both sides

1.47 = 2v^2

divide by 2 on both sides

.735 = v^2

take square root of both sides

\sqrt{.735)  or .85732141

7 0
3 years ago
A group of students left school at 8:00 am on a field trip to a science museum 90 miles away. Which best describes the average s
Aliun [14]

Answer:

45

Explanation:

because the equation for speed is distance divided by time! hope that helps gave a nice day!

7 0
3 years ago
6. Decelerating a plane at a uniform rate of -8 m/s2, a pilot stops the plane in 484 m. How
uysha [10]

Answer: 88 m/s

Explanation:

If we are talking about an acceleration at a uniform rate, we are dealing with constant acceleration, hence we can use the following equation:

{V_{f}}^{2}={V_{o}}^{2}+2ad (1)

Where:

V_{f}=0 Is the final velocity of the plane (we know it is zero because we are told the pilot stops the plane at a specific distance)

V_{o} Is the initial velocity of the plane

a=-8m/s^{2} is the constant acceleration of the plane

d=484m is the distance at which the plane stops

Isolating  V_{o} from (1):

V_{o}=\sqrt{-2ad} (2)

V_{o}=\sqrt{-2(-8m/s^{2})(484m)} (3)

Finally:

V_{o}=88m/s This is the veocity the plane had before braking began

8 0
3 years ago
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