This is my notes from last year my teacher really dumbed it down for us lol and it really helped but I'm not so sure if ur question would be answer with this but ik it will help with other problems for Physics I just thought I would share it I hope this helps have a lovely nite and good luck with this question let me know if the pics are good or not!
Answer:
(a) 2.03 m/s
(b) 2.15 m/s
Explanation:
(a)
From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum
Momentum, p=mv where m is the mass and v is the velocity
where
is the common velocity,
and
are velocities of the first railroad car and the second railroad car respectively,
and
are masses of the first railroad car and the second railroad car respectively
Substituting the given figures then

(b)
Momentum, p=mv where m is the mass and v is the velocity
where
and
are initial velocities of the ball moving towards west and the other ball moving in opposite direction respectively,
and
are masses of the first railroad car and the second railroad car respectively
Taking west as positive then the opposite direction will be negative hence

Note that when the 0.455 rebounds, it moves towards East and since we took West as positive that is why we give 15.4 as a negative value.
towards East
Answer: sq. root of .735
Explanation:
multiply two on both sides.
(2) *2,94 = (0,200 * v^2) (2)
588 = 0400 * 2v^2
divide by 400 on both sides
1.47 = 2v^2
divide by 2 on both sides
.735 = v^2
take square root of both sides
or .85732141
Answer:
45
Explanation:
because the equation for speed is distance divided by time! hope that helps gave a nice day!
Answer: 88 m/s
Explanation:
If we are talking about an acceleration at a uniform rate, we are dealing with constant acceleration, hence we can use the following equation:
(1)
Where:
Is the final velocity of the plane (we know it is zero because we are told the pilot stops the plane at a specific distance)
Is the initial velocity of the plane
is the constant acceleration of the plane
is the distance at which the plane stops
Isolating
from (1):
(2)
(3)
Finally:
This is the veocity the plane had before braking began