Answer:
Linear motion in which the direction of the velocity remains constant and the path is a straight line.
Answer:
L^2T^-1
Explanation:
a = vr
The dimension of v is LT^-1
The dimension of r is L
Therefore, the dimension of a = LT^-1 × L = L^2T^-1
She misses. She should have accelerated faster in order to get to her target.
Answer: 0.03 N/C
Explanation:
We use the current density formula to solve this question.
I/A = σ * E
Where,
I = current flowing in the circuit = 0.3 A
A = cross sectional area of the wire = 1 mm²
σ = resistivity of the wire = 1*10^7 Ω^-1·m^-1
E = strength of the electric field required
I/A = σ *E
E = I/(A * σ)
First we convert area from mm to m, so that, 1*10^-3 mm = 1*10^-6 m
E = 0.3 A / (1*10^-6 m * 1*10^7 Ω^-1·m^-1)
E = 0.3 A / 10 Ω^-1
E = 0.03 N/C
