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3 years ago

Which type of comb would be best to use in the winter, a plastic comb or a glass comb? Explain using the Triboelectric series.

Physics

1 answer:

leonid [27]3 years ago

7 0

Answer:

I'm not sure how to use it using the Series, but it would be the plastic comb

Explanation:

In the winter, it's likely to be cold and the glass would absorb that energy, also making it cold. in order to be able to hold it, you would need something warm, thus making the plastic one the better option as it is less likely to absorb the cold energy

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An object is dropped from a height of 25 meters. At what velocity will it hit the ground?

Goryan [66]

You can use Vf^2-Vi^2 = 2ax

Vf^2 - 0 = 2(9.81)(25)

Or you can use energy

mgh = 1/2mv^2

2gh =v^2

Same thing

6 0

3 years ago

(a) Find the magnitude of an earthquake that has an intensity that is 37.25 (that is, the amplitude of the seismograph reading i

MAVERICK [17]

Answer:

The magnitude of an earthquake is 5.6.

Explanation:

The magnitude of an earthquake can be found as follows:

$M = log(\frac{I}{S})$

Where:

I: is the intensity of the earthquake = 37.25 cm

S: is the intensity of a standard earthquake = 10⁻⁴ cm

Hence, the magnitude is:

$M = log(\frac{I}{S}) = log(\frac{37.25}{10^{-4}}) = 5.6$

Therefore, the magnitude of an earthquake is 5.6.

I hope it helps you!

6 0

3 years ago

1. An 800-gram bowling ball is rolling in a straight line toward you. If its momentum is 16 kg•m/sec, how fast is it traveling?

ziro4ka [17]

Answer:

The ball is rolling at a speed of 0.02 meter per second.

Step by step explanation:

We are given that there is a 800 gram bowling ball rolling in a straight line. If its momentum is given to be 16 kg.m/sec, we are to find its velocity.

For this, we will use the formula of momentum.

Momentum = mass × velocity

16 = 800 × velocity

Velocity = 16/800 = 0.02 meter per second

3 0

3 years ago

A kite 40 ft above the ground moves horizontally at a constant speed of 10 ft/s, with a child, holding the ball of kite string,

Lorico [155]

Answer:

v = 27.28 m /s, θ = 63.9º

Explanation:

For this exercise we can approximate the movement to a projectile launch, let's analyze the situation.

* We must find the horizontal speed, for this we will find the descent time and the horizontal distance

* We look for the vertical speed

At the highest point the speed is horizontal

Let's find the time it takes for the kite to reach the ground

y = y₀ + v_{oy} t - ½ g t²

0 =y₀ + 0 -1/2 gt²

t = $\sqrt{ \frac{2y_o}{g} }$

t = √(2 40/32)

t = 2.5 s

to find the horizontal velocity we must know the horizontal distance, let's use trigonometry

sin θ = y / l

θ = sin⁻¹1 y / l

θ = sin⁻¹ 40/50

θ = 53.1º

therefore the horizontal distance is

x = l cos 53.1

x = 50cos 53.1

x = 30 m

let's use the equation

x = v₀ₓ t

v₀ₓ = x / t

v₀ₓ = 30 / 2.5

v₀ₓ = 12 m / s

we look for the vertical component of the velocity

v_y = v_{oy} - g t

v_y = 0 - g t

v_y = - 9.8 2.5

v_y = -24.5 m / s

the negative sign indicates that the speed is directed downwards, because it is the arrival point, as they indicate that there is no friction, the exit speed is the same, worse with the opposite sign

We already have the two components of the velocity, let's use the Pythagorean theorem to find the modulus

v = $\sqrt{v_x^2 + v_y^2}$