1. f1 = Vs + Vbat Vs fO
2. f1 = Vs Vs - Vbat fO
3. f1 = Vs Vs + Vbat fO
4. f1 = Vs + Vbat Vs - Vbat fO
5. f1 = 2Vs Vs - Vbat fO
6. f1 = Vs - Vbat Vs fO
7. f1 = Vs - Vbat Vs + Vbat fO
8. f1 = fO
9. f1 = 2Vs Vs + Vbat fO
The observed frequency is
f= (V+Vr) × fO/ (V + Vs)
The speed of the sound is V = Vs
The speed of the receiver is Vr = O
The speed of the source
Vs = -Vbat where negative is the bat which is approaching the wall
Then the correct answer is
f1 = (Vs / (Vs -Vbat)) × fO.
Answer:
55.84 look at periodic table
so 55.84*3= 167.52gFe
Answer:
The answer is C. it will evaporate.
Explanation:
Answer:
0.48 kgm/s
Explanation:
= mass of the particle = 2.43 μg = 2.43 x 10⁻⁶ x 10⁻³ kg = 2.43 x 10⁻⁹ kg
= velocity of the particle = 1.97 x 10⁸ m/s
= momentum of the particle
momentum of the particle is given as
inserting the values
![p = (2.43\times 10^{-9})(1.97\times 10^{8})](https://tex.z-dn.net/?f=p%20%3D%20%282.43%5Ctimes%2010%5E%7B-9%7D%29%281.97%5Ctimes%2010%5E%7B8%7D%29)
kgm/s