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mina [271]
2 years ago
13

How do i get boys to like me?

Mathematics
1 answer:
meriva2 years ago
3 0
Start looking like the standards because y’all starting to look the same
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5/6(1/2(12)+6)-3(12)
zimovet [89]

Answer:

-26

Step-by-step explanation:

3 0
3 years ago
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Use the following set of data: 5, 7, 7, 6, 4, 8, 17, 5, 7, 5, 6, and 5. Find the interquartile range of the data. *
Leviafan [203]

The answer is 2 because The interquartile range (IQR) is a number that indicates how spread out scores are and tells us what the range is in the middle of a set of scores.

For extra im going to tell you all the quartile ranges.

First Quartile-5

Third Quartile-7

Median-6

Interquartile-2

7 0
3 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
koban [17]

Answer:

a) No, because the probabilities of winning the 2nd game are dependant on the result of the 1st game. The probabilities are different if you win or lose the first game.

b) P=0.42

c) P=0.08

d)

X    |    P(X)

------------------

0    |    0.42

1     |    0.50

2    |    0.08

e) E(x)=0.66

s.d.=0.62

Step-by-step explanation:

a) No, because the probabilities of winning the 2nd game are dependant on the result of the 1st game. The probabilities are different if you win or lose the first game.

b) The probability of losing the first game is

P(G_1=L)=1-P(G_1=W)=1-0.4=0.6

The probability of losing the second game, given that the first game was lost is:

P(G_2=L|G_1=L)=1-P(G_2=W|G_1=L)=1-0.3=0.7

So the probability of losing both games is:

P(G_2=L\&G_1=L)=P(G_1=L)*P(G_2=L|G_1=L)=0.6*0.7=0.42

c) The probability of winning both games is:

P(G_2=W\&G_1=W)=P(G_1=W)*P(G_2=W|G_1=W)=0.4*0.2=0.08

d) The variable X can take values 0, 1 and 2.

X=0 is when both games are lost. This happens with probability P=0.42.

X=2 is when both games are won. This happens with probability P=0.08.

X=1 is when one game is won and the other is lost. This happens with probability P=1-0.42-0.08=0.50.

Then the table of probabilities become:

X    |    P(X)

------------------

0    |    0.42

1     |    0.50

2    |    0.08

e) The expected value is:

E(x)=\sum p_ix_i=0.42*0+0.50*1+0.08*2=0.00+0.50+0.16=0.66

The variance and standard deviation of x are:

V(x)=\sum p_i(x_i-E(x))^2\\\\V(x)=0.42(0-0.66)^2+0.50(1-0.66)^2+0.08(2-0.66)^2\\\\V(x)=0.42*0.4356+0.50*0.1156+0.08*1.7956\\\\V(x)=0.183+0.058+0.144=0.385\\\\\\\sigma=\sqrt{V(x)}=\sqrt{0.385}=0.62

The standard deviation can

5 0
3 years ago
Simplify
Whitepunk [10]
Here is the solved answer for this question

7 0
2 years ago
Masha is making a scale diagram of the front face of an aquarium. The face is shaped like a rectangle.
Marat540 [252]
Scale:
1 cm : 6 inches

---------------------------------
Length of the aquarium:
---------------------------------
5 feet = 5 x 12 = 60 inches
60 ÷ 6 = 10 
The length will be 10 cm on the scale drawing.

---------------------------------
Width of the aquarium:
---------------------------------
2 feet = 2 x 12 = 24 inches
24 ÷ 6 = 4 

The width will be 4 cm on the scale drawing.

---------------------------------
Find Perimeter:
---------------------------------
Perimeter = 2 (length + width)
Perimeter = 2( 10 + 4 )
Perimeter = 28 cm

--------------------------------------------------------------------------------------------------
Answer:  The perimeter of the scale drawing of the front face is 28 cm.--------------------------------------------------------------------------------------------------

4 0
3 years ago
Read 2 more answers
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