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san4es73 [151]
3 years ago
10

Name the following straight-chain

Chemistry
1 answer:
lana66690 [7]3 years ago
6 0
I think it’s octane 35% sure it is
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Can someone help me please
kap26 [50]
(3 x 10^10 Hg) x (1 mole Hg/6.022 x 10^23 Hg) x (200.59g / 1 mole Hg) =
99.928 x 10^-13
10^-9 g Hg x (1 mole Hg / 200.59 g Hg) x (6.022 x 10^23 Hg / 1 mole Hg) =
0.031 x 10^14 Hg = 3.1 x 10^12 Hg
I.) 10^-11 g Hg
II.) 3.1 x 10^12 Hg

4 0
2 years ago
Consider the equation below.
V125BC [204]

Answer:

1:1

Explanation:

There is one mole of zinc (Zn) and one mole of zinc sulfate (ZnSO₄).

The mole ratio is 1:1.

Hope this helps.

8 0
2 years ago
The process by which a semipermeable membrane allows water molecules, small molecules, and ions to pass through while retaining
Jet001 [13]
The process is know as diffusion in which substances move from higher concentration to lower concentration
5 0
3 years ago
Which of the following changes to a pipe would increase the conductance by a factor of 12?
ivanzaharov [21]

C. Tripling the length and reducing the radius by a factor of 2 is the change to a pipe would increase the conductance by a factor of 12.

<u>Explanation:</u>

As we know that the resistance is directly proportional to the length of the pipe and it is inversely proportional to the cross sectional area of the pipe.

So it is represented as,

R∝ l /A [ area is radius square]

So k is the proportionality constant used.

R = kl/A

Conductance is the inverse of resistance, so it is given as,

C= 1/R.

R₁ = kl₁ / A₁

R₂ = kl₂/A₂

R₂/R₁ = 1/12 [∵ conductance is the inverse of resistance]

        = l₂A₁ / l₁A₂

If we chose l₁/l₂= 3 and A₂/A₁= 4 So R₂/R₁= 1/3×4 = 1/12

So tripling the length and reducing the radius by a factor of 2 would increase the conductance by a factor of 12.

6 0
3 years ago
Why is Oxygen classified as an element?
UNO [17]


It can be oxygen in only 1 atom. All elements on the periodic table can stand alone in one atom.

(I took a lucky guess, using some of my knowledge about elements )


7 0
3 years ago
Read 2 more answers
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