1 answer:
Answer:
1.51 × 10⁶ kJ
General Formulas and Concepts:
<u>Stoichiometry</u>
Using Dimensional Analysis <u>Thermochemistry</u>
Specific Heat Formula: q = mcΔT
<em>q</em> is heat (in J) <em>m</em> is mass (in g) <em>c</em> is specific heat formula (in J/g °C) <em>ΔT</em> is change in temperature (in °C) Explanation:
<u>Step 1: Define</u>
[Given] m = 114.32 g
[Given] c = 4186 J/kg °C
[Given] ΔT = 18.0 °C - 14.85 °C = 3.15 °C
[Solve] <em>q</em>
<em />
<u>Step 2: Convert Pt. 1</u>
1 kg = 1000 g
<u>Step 3: Solve</u>
Substitute in variables [Specific Heat Formula]: q = (114.32 g)(418600 J/g °C)(3.15 °C) Multiply: q = (4.78544 × 10⁸ J/°C)(3.15 °C) Multiply: q = 1.50741 × 10⁹ J
<u>Step 4: Convert Pt. 2</u>
1000 J = 1 kJ
<u>Step 5: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs as our lowest.</em>
1.50741 × 10⁶ kJ ≈ 1.51 × 10⁶ kJ
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